No because the exponent on 6^3 is 216 and if you use (4•6)^3 then you’ll have to multiply the quotations and then Square it to the third
Answer:
|F net| = 20.22 N
θ ≈ 19.8°
Step-by-step explanation:
F net = 15N i + 8cos(60°)N i + 8sin(60°)N j
= 15N i + 8×½N i + 8×√3/2N j
= 15N i + 4N i + 4√3N j
= 19N i + 4√3N j
|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N
tan(θ) = 4√3 ÷ 19 ≈ 0.36 → θ ≈ arctan(0.36) = 19.8°
Answer:
25%
Step-by-step explanation:
An easy way to figure this out is just by dividing the initial amount of students (18) by the current amount of students (24), and then subtracting 1.
So, 18/24 = 0.75 (aka 75%), and 1 - 0.75 = 0.25 (aka 25%)
Answer:
x is less than -3
Step-by-step explanation:
3x^2+9x<0
x^2+3x<0
x(x+3)<0
x+3<0
x<-3
