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1 year ago

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A balance and a graduated cylinder are used to determine the density of a mineral sample. The sample has a mass of 16 g and a vo

lume of 2 cm3. What is the density of the mineral sample?

1 answer:

Ludmilka [50]1 year ago

6 0

Answer:

8g/cm³

Explanation:

density is mass per unit volume , it is measured in grams per unit volume

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If a screwdriver was used to pry open a door, where would scratches/striations be found?

scZoUnD [109]

Answer:

it would be in the keyhole probably

Explanation:

Because you would have to put the screwdriver inside to try and break the lock

3 0

3 years ago

Read 2 more answers

What volume of 1.75 M hydrochloric acid (HCl aq) must be diluted with water to prepare 0.500 L of 0.250 M hydrochloric acid?

Airida [17]

Answer:

$V_1=0.0714L$

Explanation:

Hello there!

In this case, since we need to dilute the 1.75-M HCl, and the total number of moles remain unchanged, we can write:

$n_1=n_2$

And in terms of volume and concentration:

$C_1V_1=C_2V_2$

Thus, we can solve for the volume of the concentrated HCl as shown below:

$V_1=\frac{C_2V_2}{C_1}$

Therefore, we plug in the data to get:

$V_1=\frac{0.250M*0.500L}{1.75 M}\\\\V_1=0.0714L$

Best regards!

7 0

3 years ago

2. A 10.0 g ice cube, initially at 0.0ºC, is melted in 100.0 g of water that was initially 20.0ºC. After the ice has melted, the

arlik [135]

Answer:

The heat lost by the water $Q_{water} =$ 3.8 KJ

The heat gain by ice $Q_{ice}$ = 228.76 J

The heat required to melt the ice $Q_{melt}$ = 3340 J

Explanation:

Mass of ice cube $m_{ice}$ = 10 gm

Initial temperature of ice cube $T_{ice}$ = 0 °c

Mass of water $m_{water}$ = 100 gm

Initial temperature of water $T_{w}$ = 20 °c

Final temperature of mixture $T_{f}$ = 10.93 °c

(a). Total heat lost by the water $Q_{water} =$ $m_{water}$ $C_{w}$ ( $T_{f}$ - $T_{w}$ )

⇒ $Q_{water} =$ 100 × 4.184 (20 - 10.93)

⇒ $Q_{water} =$ 3.8 KJ

This is the heat lost by the water.

(b). Heat gained by the ice cube $Q_{ice}$ = $m_{ice}$ $C_{ice}$ $(T_{f} - T_{ice} )$

⇒ $Q_{ice}$ = 10 × 2.093 × ( 10.93 - 0)

⇒ $Q_{ice}$ = 228.76 J

This is the heat gain by ice.

(C). Heat required to melt the ice $Q_{melt}$ = $m_{ice}$ × Latent Heat

⇒ $Q_{melt}$ = 10 × 334

⇒ $Q_{melt}$ = 3340 J

This is the heat required to melt the ice.

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3 years ago

Whats the difference between covalent and ionic bonds

il63 [147K]

Answer: The two main types of chemical bonds are ionic and covalent bonds. An ionic bond essentially donates an electron to the other atom participating in the bond, while electrons in a covalent bond are shared equally between the atoms. The only pure covalent bonds occur between identical atoms.Jan 23, 2020

Explanation: Hope this helped!!!!

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3 years ago

Calculate the value of ΔG∘rxnΔGrxn∘ for the following reaction at 296 K. Ka = 2.9 × 10–8 and assume Ka does not change significa

oee [108]

Answer:

$\Delta G_{rxn}=42.7\frac{kJ}{mol}$

Explanation:

In this case, for the dissociation of hypochlorous acid, we know that the acid dissociation constant (Ka) is 2.9x10⁻⁸, which is related with the Gibbs free energy as shown below:

$\Delta G_{rxn}=-RTln(K)$

But in this case K is just Ka, therefore, at 296 K, it turns out:

$\Delta G_{rxn}=-8.314\frac{J}{mol*K}*296K*ln(2.9x10^{-8})\\\\\Delta G_{rxn}=42.7\frac{kJ}{mol}$

Such result, means that the reaction is nonspontaneous at the given temperature, it means it is not favorable (not easily occurring).

Best regards.

7 0

3 years ago