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amm1812
3 years ago
15

How many oxygen molecules are required for glycolysis

Chemistry
2 answers:
morpeh [17]3 years ago
6 0

Answer:

0

Explanation:

glycolysis requires no oxygen

ale4655 [162]3 years ago
3 0
Answer
Glycolysis requires no oxygen. It is an anaerobic type of respiration performed by all cells, including anaerobic cells that are killed by oxygen.
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The picture shows two containers filled with a gas.
aniked [119]

Answer: The average kinetic energy of the gas particles is greater in container B because it has a higher temperature.

3 0
2 years ago
The combustion method used to analyze for carbon and hydrogen can be adapted to give percentage N by collecting the nitrogen fro
12345 [234]

Answer:

The percentage of N in the compound is 0.5088

Explanation:

Mass of compound = 8.75 mg = 8.75×1000 = 8750 g

Mass of N2 = number of moles of N2 × MW of N2 = 1.59 × 28 = 44.52 g

% of N in the compound = (mass of N2/mass of compound) × 100 = (44.52/8750) × 100 = 5.088×10^-3 × 100 = 0.5088

6 0
3 years ago
Read temprature on thermometer i am confusion
balu736 [363]

Answer:

a)22.2°C after adding magnesium

b)17.3°C before adding magnesium

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8 0
3 years ago
What would happen if carbon -14 gained 1 proton and lost 1 neutron?
sleet_krkn [62]
D. To answer this question refer to the periodic table and think logically about it. Adding one proton increases the atomic number so you go along the row to Nitrogen. If you lose one neutron then the atomic mass decreases by 1 so 14-1 is 13.
4 0
3 years ago
3) During the day at 27°C a cylinder with a sliding top contains 20.0 liters
tatiyna

Answer:

T_2=12\°C

Explanation:  

Hello there!  

In this case, according to the Charles' law equation which help us to understand the directly proportional relationship between volume and temperature:

\frac{T_2}{V_2}=\frac{T_1}{V_1}  

Thus, by solving for the final temperature, T2, and making sure we use the temperatures in Kelvin, we can calculate the final temperature as shown below:

T_2=\frac{T_1V_2}{V_1}  \\\\T_2=\frac{(27+273)K*19L}{20.0L}\\\\T_2=285-273\\\\T_2=12\°C

Best regards!  

Best regards!

4 0
3 years ago
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