Which of the following is a productivity strategy for collaboration?
-
A. Saving focused work for a time of day when you feel most creative.
- B. Employing the 80/20 rule to prioritize tasks.
- C. Posting files to a web-based shared site.
- D. Using white noise to block distractions in the office.
<u>Answer:</u>
Posting files to a web-based shared site is a productivity strategy for collaboration.
- C. Posting files to a web-based shared site.
<u>Explanation:</u>
Collaborative software or groupware is application programming intended to help individuals taking a shot at a typical errand to achieve their objectives. This permits individual to impart thoughts and their abilities to different individuals with the goal that the assignment can be done both proficiently and adequately.
Joint effort stages ordinarily incorporate an email customer, Web conferencing, internet based life sharing, video capacities, report sharing abilities, texting and that's just the beginning. Endeavor joint effort stages are intended to be introduced on-premises or conveyed by means of the Web as cloud-based administrations.
Answer:
To check if the year comes under each 100th year, lets check if the remainder when dividing with 100 is 0 or not.
Similarly check for 400th year and multiple 0f 4. The following C program describes the function.
#include<stdio.h>
#include<stdbool.h>
bool is_leap_year(int year);
void main()
{
int y;
bool b;
printf("Enter the year in yyyy format: e.g. 1999 \n");
scanf("%d", &y); // taking the input year in yyyy format.
b= is_leap_year(y); //calling the function and returning the output to b
if(b==true)
{
printf("Thae given year is a leap year \n");
}
else
{
printf("The given year is not a leap year \n");
}
}
bool is_leap_year(int year)
{
if(year%100==0) //every 100th year
{
if(year%400==0) //every 400th year
{
return true;
}
else
{
return false;
}
}
if(year%4==0) //is a multiple of 4
{
return true;
}
else
{
return false;
}
}
Explanation:
Output is given as image
Answer: True
Explanation: The potential error in Word is defined as the error that arises when it tries to post some content or text but the user is not sure whether it is posted or not.In Word, the error is relate top the spellings, phrase,grammar etc, in which the Word tries to give alternatives to the particular word or text.
The error is marked with the underline that can be red which means the spelling is incorrect ,green shows some grammatical error and blue is for the inconsistency in the format. Thus, the given statement is true.
Answer:
import regex as re
def in_parentheses(a_string):
regeX = re.compile(".*?\((.*?)\)")
result = re.findall(regeX, a_string)
return str(result).replace("[","").replace("]","")
print("test 1: "+in_parentheses("Open ( only"))
print("test 2: "+in_parentheses("This is a sentence (words!)."))
