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Monica [59]
10 months ago
13

What is the solution to 2.1(2.3 + 2.1x) = 11.65 + x? A . 4.5 B . 1.5 C . 3 D . 2

Mathematics
1 answer:
Ierofanga [76]10 months ago
7 0

Answer:

2

Step-by-step explanation:

Distribute

4.83+4.41x=11.65+x

Subtract 1x

4.83+3.41x=11.65

subtract 4.83

3.41x=6.82

Divide by 3.41

x=2

Hope this helped!

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Tara scored 20 points in her first basketball game and n points in each of the next 6 games. What expression represents tara's t
Karo-lina-s [1.5K]

Answer:

  20+6n

Step-by-step explanation:

Tara's point total is found by adding up the points in each game ...

  20 + n + n + n + n + n + n

  = 20 +6n

_____

Of course, we use multiplication to simplify repeated addition.

6 0
3 years ago
What is 11/9 reduced to a mixed number?? i cant figure this out
vodomira [7]
Answer:

11/9

=9/9+2/9

=1+2/9
3 0
3 years ago
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Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste
lidiya [134]

Answer:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).  

Solution to the problem

For this case we have the following distribution given:

X          3      4       5        6

P(X)   0.07  0.4  0.25  0.28

We can calculate the mean with the following formula:

E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74

In order to find the variance we need to calculate first the second moment given by:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36

And the variance is given by:

Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924

And the deviation would be:

Sd(X) =\sqrt{0.8924} =0.9447

3 0
3 years ago
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Andrew [12]

Answer:

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Step-by-step explanation:

<u>Which number is the largest? </u>

  • 1.2 × 10^4
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8 0
3 years ago
A rectangular garden is 15 ft longer than it is wide. Its area is 700 ft. What are its dimensions?
ipn [44]
20ft and 35ft are the dimensions
8 0
2 years ago
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