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Korolek [52]
1 year ago
10

seven people arrive to dinner, but the circular table only seats six. if two seatings such that one is a rotation of the other a

re considered the same, then in how many different ways can we choose six people and seat them at the table?
Mathematics
1 answer:
Alenkinab [10]1 year ago
5 0

6 different people chosen from 7 can sit around the circular table in 840 ways.

Given that there are 7 people who have arrived for dinner.

But the circular table only seats 6.

Hence 1 person can be left out.

This can be done in 7 ways, which is a simple case of permutation.

A permutation is a combination of objects arranged in a particular sequence. The elements of sets are arranged in this case in a linear or sequential sequence.

Now 6 people will have to sit on the circular table.

Now from the properties of combination we know that , if n people sit around a circular table, then they can sit in n! ways.

Therefore 6 people can sit around a circular table in 6! ways.

6! = 120

Therefore total number of ways = 120 × 7 = 840

Hence 6 different people chosen from 7 can sit around the circular table in 840 ways.

To learn more about table visit:

brainly.com/question/16885576

#SPJ4

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san4es73 [151]
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