Yes, you multiply the numerator by the numerator and the denominator by the denominator
An easy way to do this is to do trial and error.
All possible places to put the bracket:
a) (25 - 8) - 2 = 19 But since BEDMAS goes from left to right with Addition and Subtraction, the equation is unaffected.
b) 25 - (8 - 2) = 19
25 - 6 = 19
Therefore b) is correct.
A quadrilateral is a four-sided two-dimensional shape. The following 2D shapes are all quadrilaterals: square, rectangle, rhombus, trapezium, parallelogram and kite.
Answer:
The probability of winning directly is, as you calculated, 8/36, and the probability of losing directly is (1+2+1)/36=4/36.
For the remaining cases, you need to sum over all remaining rolls. Let p be the probability of rolling your initial roll, and q=6/36=1/6 the probability of rolling a 7. Then the probability of rolling your initial roll before rolling a 7 is p/(p+q), and the probability of rolling a 7 before rolling your initial roll is q/(p+q). Thus, taking into account the probability of initially rolling that roll, each roll that doesn't win or lose directly yields a contribution p2/(p+q) to your winning probability.
For p=5/36, that's
(536)25+636=2511⋅36,
and likewise 16/(10⋅36) and 9/(9⋅36) for p=4/36 and p=3/36, respectively. Each of those cases occurs twice (once above 7 and once below), so your overall winning probability is
836+236(2511+1610+99)=244495=12−7990≈12−0.007.
Step-by-step explanation:
Suppose you throw a 4 and let p(4) your winning probability. At your next roll you have a probability 3/36 of winning (you throw a 4), a probability 6/36 of losing (you throw a 7) and a probability 27/36 of repeating the whole process anew (you throw any other number). Then:
p(4)=336+2736p(4),so thatp(4)=13.
Repeat this reasoning for the other outcomes and then compute the total probability of winning as:
ptot=836+336p(4)+436p(5)+…
Answer:
infinite solutions
x is all real numbers
Step-by-step explanation:
2x+1+x=3(x-2)+7
Distribute
2x+1 +x = 3x -6+7
Combine like terms
3x+1 = 3x+1
Subtract 3x from each side
3x-3x+1 = 3x-3x+1
1=1
This is always true, so it doesn't matter what value we put in for x
X is all real numbers
