Answer: She invested $5000 in an account that pays 6% interest and $10000 in an account that pays 7% interest.
Step-by-step explanation:
Let P be the initial amount she invested in an account that pays 6% interest.
Then, amount invested in other account = 2P
Simple interest = Principal x rate x time
After one year, for the first account,
Interest = P(0.06)(1) = 0.06P
For second account,
Interest = (2P)(0.07)(1)=0.14P
Total interest = 

2P = 2(5000)=10000
Hence, She invested $5000 in an account that pays 6% interest and $10000 in an account that pays 7% interest.
Answer:y=0.5x+10
Step-by-step explanation:
need help with explanation?
Answer:
The answer to this question is A >
Step-by-step explanation:
I got it right on edge 2020 :)
0.3 times 100 = 30
300 thousands = 0.300.
No it does not
(3x^5y)^2=
3^2=9
(x^5)^2=x^10
y^2=y^2
(3x^5y)^2=9x^10y^2
9x^10y^2(4x^3y^5)=
9*4=36
x^10*x^3=x^13
y^2*y^5=y^7
9x^19y^2(4x^3y^5)= 36x^13y^7
Final answer: 36x^13y^7