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1 year ago

based on distance to the nearest water well, which drilling site would pose the least risk of methane contamination?

1 answer:

7 0

Based on distance to the nearest water well, the drilling site that would pose the least risk of methane contamination would be the one farthest away from the water well.

Methane is a gas that is known to escape from the ground and rise up into the atmosphere. If the drilling site is too close to the water well, there is a greater risk that the methane could contaminate the water.

The atmosphere is the air that surrounds us. It is a mixture of gases, including nitrogen, oxygen, and carbon dioxide. The atmosphere protects us from the Sun's ultraviolet radiation and from the cold of space. It also contains the Earth's weather, which is caused by the Sun's energy.

Learn more about Methane at : brainly.com/question/2127750

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2Mg + O2 → 2MgO If you are burning 5.8332 g of Mg, how many grams of MgO will this make?

LekaFEV [45]

<h3>Answer:</h3>

9.6724 g MgO

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Stoichiometry

Reading a Periodic Table
Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

[RxN - Balanced] 2Mg + O₂ → 2MgO

[Given] 5.8332 g Mg

Step 2: Identify Conversions

[RxN] 2 mol Mg = 2 mol MgO

Molar Mass of Mg - 24.31 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of MgO - 24.31 + 16.00 = 40.31 g/mol

Step 3: Stoichiometry

Set up: $\displaystyle 5.8332 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg})(\frac{2 \ mol \ MgO}{2 \ mol \ Mg})(\frac{40.31 \ g \ MgO}{1 \ mol \ MgO})$
Multiply/Divide: $\displaystyle 9.67241 \ g \ MgO$

Step 4: Check

Follow sig fig rules and round. We are given 5 sig figs.

9.67241 g MgO ≈ 9.6724 g MgO

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