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Zolol [24]
3 years ago
12

Help me to balance this equations pls! C3H8 02 CO+H20 Thank you

Chemistry
1 answer:
vichka [17]3 years ago
8 0

Answer:

2C3H8 402 6CO+8H20

Explanation:

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3 0
3 years ago
Together oxygen and nitrogen comprise what percentage of the atmosphere
Charra [1.4K]
Oxygen is 21% and nitrogen is 78% so combined is 99%
5 0
3 years ago
Sample of 200mls of 0.5 sulphuric acid,was asked to produce 1.2M of the new solution.Calculate the volume of the new solution​
AlladinOne [14]

Answer:

V_2=83.3mL

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the volume of the new solution by using the general formula of dilution:

V_1M_1=V_2M_2

In such a way, we solve for the final volume, V2, to obtain:

V_2=\frac{200mL*0.5M}{1.2M}\\\\V_2=83.3mL

Regards!

3 0
3 years ago
4. Which of these metals is a pure element? Brass Bronze Silver Steel 5. C is the correct chemical symbol for ....... Calcium Ca
Gala2k [10]

Answer:

4) Silver

5) Carbon

6) Oxygen

3 0
3 years ago
Read 2 more answers
What mass of calcium carbonate is produced when 250 mL of 6.0 M sodium carbonate is added to 750 mL of 1.0 M calcium fluoride
Savatey [412]

<u>Given:</u>

Volume of Na2CO3 = 250 ml = 0.250 L

Molarity of Na2CO3 = 6.0 M

Volume of CaF2 = 750 ml = 0.750 L

Molarity of CaF2 = 1.0 M

<u>To determine:</u>

The mass of CaCO3 produced

<u>Explanation:</u>

Na2CO3 + CaF2 → CaCO3 + 2NaF

Based on the reaction stoichiometry:

1 mole of Na2CO3 reacts with 1 moles of Caf2 to produce 1 mole of caco3

Moles of Na2CO3 present = V * M = 0.250 L * 6.0 moles/L = 1.5 moles

Moles of CaF2 present = V* M = 0.750 * 1 = 0.750 moles

CaF2 is the limiting reagent

Thus, # moles of CaCO3 produced = 0.750 moles

Molar mass of CaCO3 = 100 g/mol

Mass of CaCO3 produced = 0.750 moles * 100 g/mol  = 75 g

Ans: Mass of CaCO3 produced = 75 g

7 0
3 years ago
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