Help me to balance this equations pls! C3H8 02 CO+H20 Thank you

Which of the following would increase the strength of an electromagnet? Check all that apply.

TiliK225 [7]

Answer: The correct statements are ; A and B.

Explanation:

The strength of the magnetic field(B) in an electromagnet can be calculated using formula:

$B=\mu\frac{N}{L}I$

$\mu$ = Relative permeability

N = number of turns

I = Current in the wire of the solenoid

L = length of the solenoid or electromagnetic

As we can see from the formula:

$B\propto N$

$B\propto I$

So, by increasing the turns and increasing current flowing through wire one can increase the strength of an electromagnet.

Hence, the correct statements are ; A and B.

5 0

3 years ago

According to reference table adv-10, which reaction will take place spontaneously?

olga_2 [115]

Missing table!! write the elements with the first letter of the symbol with Upper Caps letters!!!

http://www.chemeddl.org/services/moodle/media/QBank/GenChem/Tables/EStandardTable.htm

Ni2+ +Pb(s) → Ni(s) + Pb2+
The potential of the oxidation of Pb(s) --> Pb2+(aq) is 0.126 V
The potential of the reduction go Ni2+(aq) --> Ni(s) is -0.25 V

Add the two together and the potential for the reaction is -0.124 V (NO SPONTANEOUS THE SIGN IS NEGATIVE)

au3+ + al(s) → au(s) + al3+Au3+(aq) -> Au(s) +1.5 VAl -> Al3+ +1.66VV= 3.16 (SPONTANEOUS THE SIGN OF THE PONTENTIAL IS POSITIVE)Sr2+ + Sn(s) → Sr(s) + Sn2+

Sr2+(aq) + 2 e– Sr(s) V= -2.89V
Sn -> Sn2+ V= 0.14 V
V= -2.75 V (no spontaneous)

Fe2+ + Cu(s) → Fe(s) + Cu2+
Fe2+(aq) + 2 e– Fe(s) V= -0.44 V
Cu -> C2+ V = - 0.337V

V= - 0.777V (no spontaneous)

5 0

3 years ago

Protons and neutrons are found in the nucleus. these two types of charges are referred to collectively as _____

solmaris [256]

Answer:

Nucleon

Explanation:

4 0

3 years ago

How to solve 5gNaCl= MolE NaCl

valentinak56 [21]

0.086mole