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aalyn [17]
4 years ago
7

Refer to the figure showing a pedigree of a family affected by an x-linked recessive disorder. A female in generation 3 isn't a

carrier of the disorder. How can this be?
A. Females receive X chromosomes from this fathers only, which are unaffected in this case.
B. Females don't have X chromosomes so aren't affected by gene disorders passed on the X chromosome.
C. Females receive an X chromosomes from each point parent, but in cases of recessive disorders, the muted chromosome isn't passed on to daughters.
D. Females receive an X chromosome from each parent. If a mother is a carrier of an X-linked recessive disorder, her daughters have 50 percent chance of receiving her normal X chromosome and a 50 percent chance of receiving her mutated X chromosome.

Chemistry
2 answers:
maria [59]4 years ago
5 0

Answer:

D. Females receive an X chromosome from each parent. If a mother is a carrier of an X-linked recessive disorder, her daughters have 50 percent chance of receiving her normal X chromosome and a 50 percent chance of receiving her mutated X chromosome.

Explanation:

Females have XX chromosomes as allosomes. They receive one X chromosome from mother and one from father. The female in the III generation received both the healthy X chromosomes from each parent that is why she is not even carrier for the disease.

The modified diagram clearly indicating the genotyope of all the members of the pedigree tree is attached. In the diagram, healthy X chromosome is indicated by X while mutated X chromosome is indicated by doted X. It is clear from the diagram that this female of III generation has XX chromosomes.  

The cross for that particular female is shown as under:

                               Mother               Father

                                   ẊX      x             XY

                                  /     \                  /     \

                               ẊX     ẊY          XX    XY

XX are the allosomes of this female child.

<h2 />

kari74 [83]4 years ago
3 0

Answer: D.

Explanation: Females have XX chromosomes while males have XY

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3 years ago
How many grams of Fe3O4 are required to react completely with 300 grams of H2?
vekshin1

Answer:

2023.04 g

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Fe₃O₄ + 4 H₂ → 3 Fe +4 H₂O

From the equation, 1 mole of Fe₃O₄ reacts with 4 moles of H₂.

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=34.88 moles.

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8 0
3 years ago
If an ice cube weighing 25.0 g with an initial
riadik2000 [5.3K]

Answer:

11

∘

C

Explanation:

As far as solving this problem goes, it is very important that you do not forget to account for the phase change underwent by the solid water at

0

∘

C

to liquid at

0

∘

C

.

The heat needed to melt the solid at its melting point will come from the warmer water sample. This means that you have

q

1

+

q

2

=

−

q

3

(

1

)

, where

q

1

- the heat absorbed by the solid at

0

∘

C

q

2

- the heat absorbed by the liquid at

0

∘

C

q

3

- the heat lost by the warmer water sample

The two equations that you will use are

q

=

m

⋅

c

⋅

Δ

T

, where

q

- heat absorbed/lost

m

- the mass of the sample

c

- the specific heat of water, equal to

4.18

J

g

∘

C

Δ

T

- the change in temperature, defined as final temperature minus initial temperature

and

q

=

n

⋅

Δ

H

fus

, where

q

- heat absorbed

n

- the number of moles of water

Δ

H

fus

- the molar heat of fusion of water, equal to

6.01 kJ/mol

Use water's molar mass to find how many moles of water you have in the

100.0-g

sample

100.0

g

⋅

1 mole H

2

O

18.015

g

=

5.551 moles H

2

O

So, how much heat is needed to allow the sample to go from solid at

0

∘

C

to liquid at

0

∘

C

?

q

1

=

5.551

moles

⋅

6.01

kJ

mole

=

33.36 kJ

This means that equation

(

1

)

becomes

33.36 kJ

+

q

2

=

−

q

3

The minus sign for

q

3

is used because heat lost carries a negative sign.

So, if

T

f

is the final temperature of the water, you can say that

33.36 kJ

+

m

sample

⋅

c

⋅

Δ

T

sample

=

−

m

water

⋅

c

⋅

Δ

T

water

More specifically, you have

33.36 kJ

+

100.0

g

⋅

4.18

J

g

∘

C

⋅

(

T

f

−

0

)

∘

C

=

−

650

g

⋅

4.18

J

g

∘

C

⋅

(

T

f

−

25

)

∘

C

33.36 kJ

+

418 J

⋅

(

T

f

−

0

)

=

−

2717 J

⋅

(

T

f

−

25

)

Convert the joules to kilojoules to get

33.36

kJ

+

0.418

kJ

⋅

T

f

=

−

2.717

kJ

⋅

(

T

f

−

25

)

This is equivalent to

0.418

⋅

T

f

+

2.717

⋅

T

f

=

67.925

−

33.36

T

f

=

34.565

0.418

+

2.717

=

11.026

∘

C

Rounded to two sig figs, the number of sig figs you have for the mass of warmer water, the answer will be

T

f

=

11

∘

C

Explanation:

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