A is 6/10, b is 32/45 and, c is 3/14
Answer:
Step-by-step explanation:
Solution attached below
This answer did not come from me but credit to ApusApus
We have been given that adult male heights are normally distributed with a mean of 70 inches and a standard deviation of 3 inches. The average basketball player is 79 inches tall.
We need to find the area of normal curve above the raw score 79.
First of all let us find the z-score corresponding to our given raw score.
, where,
,
,
,
.
Upon substituting our given values in z-score formula we will get,
Now we will find the P(z>3) using formula:
Using normal distribution table we will get,
Let us convert our answer into percentage by multiplying 0.00135 by 100.
Therefore, approximately 0.135% of the adult male population is taller than the average basketball player and option A is the correct choice.
Answer:
1. B
2. D
Step-by-step explanation:
Answer:
Sue was the tallest.
Step-by-step explanation:
Sally = 65 3/4 --> 65 6/8
<h2>Sue = <u>65 7/8</u></h2>
Joe = 65 1/2 --> 65 4/8