The number of possible outcomes is 8.
The probability of getting exactly one tail is 3/8.
The probability of getting at most two tails is 3/4.
<h3>What are the probabilities?</h3>
Here is the sample space if 3 coins are tossed: {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}. There are 8 possible outcomes.
The probability of getting exactly one tail = number of times only one tail is gotten / total number of possible outcomes
3/8.
The probability of getting at most two tails = number of times at most two tails is gotten / total number of possible outcomes = 6/8 = 3/4
To learn more about probability, please check: brainly.com/question/13234031
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(5.1 * (10-3)) + (3.2 * (10-3))
(5.1 * 7) + (3.2 * 7)
35.7 + 22.4
58.1
So 58.1 is the final answer! Hope this helps!
Answer:
{−9,−5,2,6,10Step-by-step explanation:
Answer:
115.3333
Step-by-step explanation:
346/3
Hope this helps. :)
Answer:
thank you for this warning
Step-by-step explanation:
ive been getting these alot lately!!
