Answer:
Step-by-step explanation:
C
l
2
+
2
K
B
r
→
2
K
C
l
+
B
r
2
Given:
300
g
of
C
l
2
300
g
of
K
B
r
(a) Mass of
C
l
2
= 300g
Molecular mass of
C
l
2
= 2(35.45) = 70.906 g
/
m
o
l
No.of moles of
C
l
2
=
m
a
s
s
/
m
o
l
a
r
m
a
s
s
=
300
/
70.906
=
4.23
moles
Mass of
K
B
r
=
300
g
Molar mass of
K
B
r
=
39
+
79.9
=
118.9
g
/
m
o
l
No.of moles of
K
B
r
=
300
/
118.9
=
2.52
moles
Now,
Consider the equation:
C
l
2
+
2
K
B
r
→
2
K
C
l
+
B
r
2
1
mole of
C
l
2
= 2 moles of
K
C
l
4.23
moles of
C
l
2
= 2x4.23=
8.46
moles
2
moles of
K
B
r
= 2 moles of
K
C
l
2.52
moles of
K
B
r
=
2.52
moles
Now convert moles to mass,
Mass of
K
C
l
produced by
C
l
2
=
8.46
×
70.906
=
599.8
g
Mass of
K
C
l
produced by potassium bromide =
2.52
×
74.5
=
187.74
g
Answer:
See below
Step-by-step explanation:
The ratio of the secants is the same when set up as full length to external length.
Formula
MN/LN = QN/PN
Givens
LN = 22 + 14 = 36
MN = 14
PN = 32
QN = x
Solution
14/36 = x / (32) Multiply both sides by 32
14*32 / 36 = x Combine 14 and 32
448/36 = x Divide by 36 and switch
x = 12.4
Answers
PN (External) = 13 is the closest answer
Length LN = 36
The answer is 4 So yeaaaa....
Answer: Yes!
Step-by-step explanation:
You correctly answered!