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tia_tia [17]
1 year ago
14

QuestionDetermine the value(s) for which the rational expressionlist them separated by a comma, e.g. n = 2,3.-3n + 12is undefine

d. If there's more than one value,84n2 + 76n +16
Mathematics
1 answer:
seraphim [82]1 year ago
5 0

A rational expression is defined for all real numbers except the zeros of the denominator.

Then, find the zeros of the denominator to find the values for which the given rational expression is undefined:

84n^2+76n+16=0

Use quadratic formula:

\begin{gathered} ax^2+bx+c=0 \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \end{gathered}\begin{gathered} n=\frac{-76\pm\sqrt[]{76^2-4(84)(16)}}{2(84)} \\  \\ n=\frac{-76\pm\sqrt[]{5776-5376}}{168} \\  \\ n=\frac{-76\pm\sqrt[]{400}}{168} \\  \\ n=\frac{-76\pm20}{168} \\  \\ n_1=\frac{-76+20}{168}=\frac{-56}{168}=-\frac{1}{3} \\  \\ n_2=\frac{-76-20}{168}=\frac{-96}{168}=-\frac{4}{7} \end{gathered}<h2>Then, the given rational expression is undefined for:</h2><h2>n= -1/3 , -4/7</h2>
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The equations -6x + 3y = 6 and x² + y = 10 intersect at the
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<u><em>a = -4</em></u>

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We are given two equations;

-6x + 3y = 6  ---(eq 1)

x² + y = 10 ---(eq 2)

  • We are told that they intersect at coordinates; (a, b) and (c, d).

Let us make y the subject in eq 2 to get;

y = 10 - x²  --(eq 3)

  • Let us put 10 - x² into eq 1 to get;

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expanding further gives;

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3x² + 6x - 24 = 0

Using online quadratic equation <em>solver</em>, we have;

x = -4 and x = 2

Putting x = -4 into eq 3 gives;

y = 10 - (-4)²

y = 10 - 16

y = -6

Putting x = 2 into eq 3 gives;

y = 10 - (2)²

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Comparing with (a, b) and (c,d), we have;

a = -4

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Read more at; brainly.com/question/15165519

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2 years ago
A pathologist knows that 14.9% of all deaths are attributable to myocardial infarctions (a type of heart disease). (Either you h
garik1379 [7]

Answer:

a) The mean number is 745 and the standard deviation is 25.18.

b) 896 deaths is a significantly high number, which means that there is cause for concern.

Step-by-step explanation:

For each death, there are only two possible outcomes. Either it is attributable to myocardial infarctions, or it is not. The probability of a death being attributable to myocardial infarctions is independent of other deaths. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

A value X is significantly high is:

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In this problem:

p = 0.149, n = 5000

a. Find the mean and standard deviation for the number of such deaths that will occur in typical region with 5000 deaths.

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\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{5000*0.149*0.851} = 25.18

The mean number is 745 and the standard deviation is 25.18.

b. In one region, 5000 death certificates are examined, and it is found that 896 deaths were attributable to myocardial infarction. Is there cause for concern? Why or why not?

Is 896 a significantly high number?

E(X) + 2\sqrt{V(X)} = 745 + 2*25.18 = 795.36

895 > 795.36

896 deaths is a significantly high number, which means that there is cause for concern.

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