Answer:
1. z^2
2. 14z
Step-by-step explanation:
- We know that (a^m)^n = a^(mn) = (a^n) ^m
We also know that (a^m)(a^n) = a^(m+n)
- 36 can be written as 6^2 and here 36^(500) can be written as (6^2)^500 which also can be written as (6^500)^2 and as already it is mentioned that 6^500 as z we can write the above as <u>z^2</u>
2. 8 x 6^500 = 8z
And we can also write 6^(501) as 6^(500+1) which is equivalent to 6(6^500) which is 6z.
From the above we can make sure that the question is the sum of the above which is 8z + 6z = <u>14z</u><u>.</u>
Step-by-step explanation:
I assume that "ground" is at 0 ft height. which is in an actual scenario not airways the case.
y = -16x² + 64x + 89
shows us that the tower is 89 ft tall (the result for x = 0, at the start).
anyway, if the original assumption is correct, then we need to solve
0 = -16x² + 64x + 89
the general solution for such a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/)2a)
in our case
a = -16
b = 64
c = 89
x = (-64 ± sqrt(64² - 4×-16×89))/(2×-16) =
= (-64 ± sqrt(4096 + 5696))/-32 =
= (-64 ± sqrt(9792))/-32
x1 = (-64 + 98.95453501...)/-32 = -1.092329219... s
x2 = (-64 - 98.95453501...)/-32 = 5.092329219... s
the negative solution for time is but useful here (it would be the time calculated back to ground at the start).
so, x2 is our solution.
the rocket hits the ground after about 5.09 seconds.
Answer:
48
Step-by-step explanation:
if you multiply 24 by 10 you get 240 then you divide that by 5 which gives you your answer of 48.
Answer:
She will pay $122.85
Step-by-step explanation:
First, find the amount of the percents.
To do that, turn the percents into decimals.
25% --> 0.25
10% --> 0.10
Then, multiply each decimal with the original price.
189×0.25= 47.25
189×0.10= 18.90
Now that you have the amount of the percents, subtract both from the original price.
189- (47.25+18.90)
189-66.15= 122.85
F(x)=x+c, where c is an arbitrary constant.
if c is positive then translation above
if c is negative then translation down
reflection of f(x)=x^2 across x-axis then
f(x)=-x^2
