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den301095 [7]
8 months ago
11

NEED HELP ASAP WILL GIVE HIGH REWARD

Mathematics
2 answers:
VikaD [51]8 months ago
4 0
The answer for this is is 35 370 93 and i got that now by using guzmos
Elanso [62]8 months ago
4 0

Answer:

Step-by-step explanation:

a.11/4*3/7=33/28

=1 whole number 5/28

b. 14.16 (0.2)

     =0.832

c.5/12 *2

     =5/6

Note the dot can be represented as multiplication sign when in the middle.

d. 4 whole number2/5*1 whole number1/3

      =22/5*4/5=88/15

      =5 whole number 13/15

2a. 3/7 divided by2/3

      =3/7*3/2

      =6/14

      =3/7

b.8  whole number2/3divided by 4 whole number 1/2

       =26/3divided by9/2

     = 26/3*2/9=52/27

    = 1 whole number 25/27

c. 1.2*0.04=0.048

d. 5.4/1*5/3

    =27.0 divided by 3

    =27/3

    =9

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PQR is a right-angled triangle. PQ = 16 cm. PR = 8 cm. Calculate the length of
vlada-n [284]
SOLUTION:

PQR is a right-angle triangle.

Therefore, to solve this problem, we will use Pythagoras theorem which is only applicable to right-angle triangles.

Pythagoras theorem is as displayed below:

a^2 + b^2 = c^2

Where c = hypotenuse of right-angle triangle

Where a and b = other two sides of right-angle triangle

Now we will simply substitute the values from the problem into Pythagoras theorem in order to obtain the length of QR.

c = PQ = 16cm

a = PR = 8cm

b = QR = ?

a^2 + b^2 = c^2

( 8 )^2 + b^2 = ( 16 )^2

64 + b^2 = 256

b^2 = 256 - 64

b^2 = 192

b = square root of ( 192 )

b = 13.8564...

b = 13.86 ( to 2 decimal places )

FINAL ANSWER:

Therefore, the length of QR is 13.86 centimetres to 2 decimal places.

Hope this helps! :)
Have a lovely day! <3
8 0
3 years ago
What is the decimal equivalent of 7 4/5?
motikmotik
It should be 7.8 which is answer D
8 0
2 years ago
Read 2 more answers
What is the gcf of 26 and 32
taurus [48]
2*13= 26
2*16= 32
the answer is 2
4 0
3 years ago
Determine the distance between the following two points. (round to the nearest hundredths)
padilas [110]

Answer:

d=7.07

Step-by-step explanation:

Distance Formula: d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>:

d=\sqrt{(3-(-2))^2+(-4-1)^2}

d=\sqrt{(3+2)^2+(-5)^2}

d=\sqrt{(5)^2+25}

d=\sqrt{25+25}

d=\sqrt{50}

d=5\sqrt{2}

d=7.07

5 0
2 years ago
Consider the line y=5/7x+7. Find the equation of the line that is parallel to this line and passes through the point (-5,-2). Fi
butalik [34]

Step-by-step explanation:

m=5/7

m1=m2=5/7

L;y-(-2)=5/7(x-(-5)

y+2=5/7(x+5)

7y+14=5X+25

7y-5x=11 is parallel lines

m1*m2=-1 is perpendicular lines

m2=-1*7/5

m2=-7/5

L;y+2=-7/5(x+5)

5Y+10=-7x-35

5y+7x=-45 is perpendicular lines

5 0
2 years ago
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