City A is 25% less than population of city B. So city A's population is 75% of city B
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<u>Solution:</u></h3>
Given that City A is 25% less than population of city B
To find: city A's population is what % of city B
From given information,
City A is 25% less than population of city B
A = B - 25% of B
So we can write as,
![A = B - \frac{25}{100} \times B\\\\A = B - 0.25B\\\\A = 0.75B](https://tex.z-dn.net/?f=A%20%3D%20B%20-%20%5Cfrac%7B25%7D%7B100%7D%20%5Ctimes%20B%5C%5C%5C%5CA%20%3D%20B%20-%200.25B%5C%5C%5C%5CA%20%3D%200.75B)
A = 0.75B can be written as,
![A = \frac{75}{100}\times B](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B75%7D%7B100%7D%5Ctimes%20B)
city A = 75 % of City B
Thus city A's population is 75% of city B
Answer:
what figure?
Step-by-step explanation:
Answer:
11.4pounds
Step-by-step explanation:
(5.58+4.68)÷0.90
=11.4(pounds)
Answer:
answer:- A
Statement: 60=3x +15; Reason: Substitution