Ok so we know that the total perimeter of the rectangle is 48m.
We also know that to get the perimeter, it is the sum of two lengths and two widths.
Therefore 2L + 2W = 48
However, we also know that the width is 2m less than the length, so the above equation can be rewritten as:
2L + 2(L-2) = 48
We can simplify this to make it
4L - 4 = 48
So 4L = 52
Hence L = 13.
We know that the width is 13-2, so the width is 11.
So the length is 13m and the width is 11m
Hope this helped
The x-coordinate changes from +3 to -3. The y-coordinate stays the same.
Answer:
0.0918
Step-by-step explanation:
We know that the average amount of money spent on entertainment is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The mean and standard deviation of average spending of sample size 25 are
μxbar=μ=95.25
σxbar=σ/√n=27.32/√25=27.32/5=5.464.
So, the average spending of a sample of 25 randomly-selected professors is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The z-score associated with average spending $102.5
Z=[Xbar-μxbar]/σxbar
Z=[102.5-95.25]/5.464
Z=7.25/5.464
Z=1.3269=1.33
We have to find P(Xbar>102.5).
P(Xbar>102.5)=P(Z>1.33)
P(Xbar>102.5)=P(0<Z<∞)-P(0<Z<1.33)
P(Xbar>102.5)=0.5-0.4082
P(Xbar>102.5)=0.0918.
Thus, the probability that the average spending of a sample of 25 randomly-selected professors will exceed $102.5 is 0.0918.
The only even numbers are 2,4,6 and the only even prime number is 2 so your answer is 1/6
Given length of the garden = 35 feet
Given width of the garden = 15 feet
Let's assume the walkway has a width of x feet.
The figure of the garden with walkway is attached below.
Length of walkway= 
Width of walkway = 
Area of walkway = length of walkway * width of walkway
Area = 
Area = 
Area = 
.... Answer
