Answer:
Step-by-step explanation:
2x²-2x=3
2x²-2x -3 = 0
note :
the discriminat of each quadratic equation : ax²+bx+c=0 ....(a ≠ 0) is :
Δ = b² -4ac
1 ) Δ > 0 the equation has two reals solutions : x = (-b±√Δ)/2a
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ < 0 : no reals solutions
***** in this exercice : a = 2 b = -2 c = -3
Δ = (-2)² -4(2)(-3) =28
x = (2±√28)/6
Answer:
X=3
C=12
Step-by-step explanation:
(2x+6)=c
2x+6
x=2/6
x=3
2x3+6=c
c=12
Answer:
x = 2
Step-by-step explanation:
Step 1 :
Equation at the end of step 1 :
(4+(4•(x-2)))-(2•(x+1)-x) = 0
Step 2 :
Equation at the end of step 2 :
(4 + 4 • (x - 2)) - (x + 2) = 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
3x - 6 = 3 • (x - 2)
Equation at the end of step 4 :
3 • (x - 2) = 0
Step 5 :
Equations which are never true :
5.1 Solve : 3 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
5.2 Solve : x-2 = 0
Add 2 to both sides of the equation :
x = 2
One solution was found :
x = 2
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X+y=6 is.....
solve for x=0... y=6
solve for y=0... x=6
intersect x-axis at (6,0)... calculate the slop: solve for x=1... 1+y=6... 6-1= 5 y=5
calculate the slope: a= y(x=1)-y(x=0)/1=-1
x+y=6
Answer: 3 x 6 + 5
or
3 x 5 + 6
or
(5 + 6) x 3
or
3 x (5 + 6)
etc.
Step-by-step explanation:
