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Citrus2011 [14]
1 year ago
5

if the price elasticity of demand for chips is 0.75, then a 20 percent increase in price would result in a _______ percent decre

ase in the quantity demanded
Mathematics
1 answer:
vladimir2022 [97]1 year ago
5 0

If the price-elasticity of demand for chips is 0.75, then a 20 percent increase in price would result in a 15 percent decrease in the demand quantity.

As per the question statement, the price-elasticity of demand for chips is 0.75 and there is a 20 percent increase in price.

We are required to calculate the resulting decrease in the demand quantity by percent, based on the conditions mentioned in the statement above.

Here, given Price-Elasticity of Demand (E_{d}) = 0.75

Also given the percent increase in price = 20

Now, we know that,

(E_{d}) = [(Percentage change in quantity demanded)/(Percentage change in price]

Or, [0.75 = (x/20)]...[Assuming "Percentage change in quantity demanded" to be "x"]

Or, [x = (20 * 0.75)]

Or, [x = 15]

That is, If the price-elasticity of demand for chips is 0.75, then a 20 percent increase in price would result in a 15 percent decrease in the demand quantity.

  • Price-Elasticity of Demand: Price Elasticity of Demand is a measurement of the change in the consumption of a product in relation to a change in its price and is expressed mathematically as the quotient of (Percentage Change in Quantity Demanded) divided by (Percentage Change in Price)

To learn more about Price-Elasticity of Demand, click on the link below.

brainly.com/question/28523466

#SPJ4

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Find BC if AC = 13 and AB = 10
maxonik [38]

Answer:

BC=3

Step-by-step explanation:

<em>We </em><em>can </em><em>solve </em><em>this </em><em>by </em><em>eliminating</em><em> </em><em>given </em><em>detail </em><em>of </em><em>A.</em>

AC=13 , AB=10

<u>To </u><u>find </u><u>BC,</u><u> </u><u>We </u><u>minus </u><u>A</u><u>C</u><u> </u><u>With </u><u>AB</u>

BC= AC-AB

<u>BC=3</u>

3 Is the final answer

I hope this helps, dont hesitate to ask for any question.

Mark me as brainliest is appreciated.Tq!!

7 0
3 years ago
Suzi bought 5 packages of M&amp;M's, and each package contained 18 candy pieces. She opened the first package and counted 4 gree
Leni [432]

Answer: The correct answer is option B: There are between 15 and 20 green pieces in all 5 packages

Step-by-step explanation: The most important factor has been given which is, "Which statement about the candy pieces in the remaining packages is best supported by this information."

The information given is such that, the first package she opened had 4 green pieces and on this basis we can safely assume that all other packages have 4 green pieces as well. The second package had 3 green pieces and this based on this too we can safely assume that all other packages had 3 green pieces. Hence, all 5 packages can either have a total of 4 x 5 green candies which equals a total of 20 green pieces or, all 5 packages can have a total of 3 x 5 green candies which equals a total of 15 green pieces.

So according to Suzi's experiment, there are between 15 and 20 green pieces in all 5 packages.

7 0
3 years ago
The USDA conducted tests for salmonella in produce grown in California. In an independent sample of 252 cultures obtained from w
Marat540 [252]

Answer:

 The decision rule is  

Fail to reject the null hypothesis

  The conclusion is  

There no sufficient evidence to show that the proportion of salmonella in the region’s water differs from the proportion of salmonella in the region’s wildlife

Step-by-step explanation:

From the question we are told that

   The first  sample size is n_1   =  252

    The number that tested positive is  k_1  =  18

     The second sample size is  n_2   =  476

     The number that  tested positive is  k_2 =  20

     The level of significance is  \alpha  = 0.01

Generally the first sample proportion is mathematically represented as

      \^ p _1 =  \frac{k_1 }{ n_1 }

=>    \^ p _1 =  \frac{18 }{ 252 }

=>    \^ p _1 = 0.071

Generally the second sample proportion is mathematically represented as

      \^ p _2 =  \frac{k_2 }{ n_2 }

=>    \^ p _2 =  \frac{20 }{ 476}

=>    \^ p _2 = 0.042

The  null hypothesis is            H_o  :  p_1 - p_2 = 0

The alternative hypothesis is  H_a :  p_1 - p_2 \ne 0

Generally the test statistics is mathematically represented

       z =  \frac{ \^ p_1 - \^ p_2  -  ( p_ 1 - p_2 )}{ \sqrt{\frac{\^ p_1 (1-\^ p_1)}{ n_1  } + \frac{\^ p_2 (1-\^ p_2)}{ n_2  }  } }

=>    z =  \frac{ 0.071 - 0.042  - 0 }{ \sqrt{\frac{0.071  (1-0.071)}{  252  } + \frac{0.042 (1-\^ 0.042)}{ 476  }  } }

=>    z =  1.56

From the z table  the area under the normal curve to the right corresponding to  1.56   is  

        P(Z >  1.56 ) =0.05938

Generally the p-value is mathematically represented as

         p-value =  2 * P(Z >  1.56 )

=>      p-value = 2 *  0.05938

=>      p-value = 0.1188

From the value obtained we see that   p-value  >  \alpha hence

  The decision rule is  

Fail to reject the null hypothesis

  The conclusion is  

There no sufficient evidence to show that the proportion of salmonella in the region’s water differs from the proportion of salmonella in the region’s wildlife

 

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Answer:

D

Step-by-step explanation:

bc it starts with -square root of 20 and then - square root of 6 and the 3.14 and then square root of 8 and then square root of 18

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