Considering the Central Limit Theorem, we have that:
a) The probability cannot be calculated, as the underlying distribution is not normal and the sample size is less than 30.
b) The probability can be calculated, as the sample size is greater than 30.
<h3>What does the Central Limit Theorem state?</h3>
It states that the sampling distribution of sample means of size n is approximately normal has standard deviation 
, as long as the underlying distribution is normal or the sample size is greater than 30.
In this problem, the underlying distribution is skewed right, that is, not normal, hence:
- For item a, the probability cannot be calculated, as the underlying distribution is not normal and the sample size is less than 30.
- For item b, the probability can be calculated, as the sample size is greater than 30.
More can be learned about the Central Limit Theorem at brainly.com/question/16695444
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Area=(1/2)bh
given
b=10
h=9
aera=(1/2)9*10=45
3 triangles+base=
45*3+43.3=
135+43.3=
178.3 mm^2
Answer:
(6,0) I think
my memory is rusty on this subject sorry if it's wrong.
Answer:
The first piece is 7 ft long, the second piece is 12 ft long, and the third piece is 13 ft long
Step-by-step explanation:
Let x represent the length of the first piece.
Since the second piece is 5 ft longer than the first, it can be represented by x + 5
Since the third piece is 1 ft longer than the second, it can be represented by x + 6
Create an equation that adds all of these terms up to 32, and solve for x
(x) + (x + 5) + (x + 6) = 32
3x + 11 = 32
3x = 21
x = 7
So, the first piece is 7 ft long.
Using the expressions we created, solve for the lengths of the second and third pieces.
x + 5
7 + 5 = 12
x + 6
7 + 6 = 13
The first piece is 7 ft long, the second piece is 12 ft long, and the third piece is 13 ft long
