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spayn [35]
3 years ago
13

$18, P = $200, r = ?, t = 1.5 years. Find the annual interest rate.

Mathematics
1 answer:
faust18 [17]3 years ago
7 0

                                                  Question 1)

Given

Interest I = $18

Principle P = $200

t = 1.5 years

To determine

Interest rate r = ?

Using the formula

P = Irt

r=\frac{I}{Pt}

susbtituting I = 18, t = 1.5 and P = 200

r=\frac{18}{\left(200\times 1.5\right)}

r = 0.06

or

r = 6%       ∵ 0.06 × 100 = 6%

Therefore, we conclude that the interest rate required to  accumulate simple interest of $18.00  from a principal of $200 over 1.5 years is 6% per year.

                                                    Question 2)

Given

Interest I = $60

Principle P = $750

Interest rate = 4% = 0.04

To determine

Time period t = ?

Using the formula to calculate the time period

P = Irt

t\:=\:\frac{P}{Ir}

t=\frac{60}{\left(750\times 0.04\right)}

t = 2 years

Therefore, the time required to  accumulate simple interest of $ 60.00

from a principal of $ 750 at an interest rate of 4% per year  is 2 years.

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Answer:

A  = 57°

B = 19°

C = 104°

Step-by-step explanation:

We have a triangle with 3 angles:

A, B, and C.

We know that:

"Angle A is 3 times larger than angle B"

We can write this as:

A = 3*B

"Angle C was 10° less than 6 times angle B"

This can be written as:

C = 6*B - 10°

And we also know that the sum of all interior angles of a triangle is 180°

Then we also have the equation:

A + B + C = 180°

So we have a system of 3 equations:

A = 3*B

C = 6*B - 10°

A + B + C = 180°

To solve this, the first step is to isolate one of the variables in one of the equations.

We can see that A is already isolated in the first one, so we can skip that step.

Now we need to replace A in the other equations, to get:

C = 6*B - 10°

(3*B) + B + C = 180°

Now we have a system of two equations.

Let's do the same procedure, we can see that C is isolated in the top equation, so we can just replace that in the other equation to get:

3*B + B + (6*B - 10°) = 180°

Now we can solve this for angle B

4*B + 6*B - 10° = 180°

10*B - 10° = 180°

10*B = 180° + 10° = 190°

B = 190°/10 = 19°

Now that we know the measure of angle B, we can input this in the equations:

A = 3*B

C = 6*B - 10°

To find the measures of the other two angles:

A = 3*19° = 57°

C = 6*19° - 10° = 104°

5 0
3 years ago
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