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Basile [38]
3 years ago
7

What is the surface area

Mathematics
2 answers:
Ivenika [448]3 years ago
4 0
348 I believe....... 
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Alina [70]3 years ago
4 0
348 is the surface area.

Hope this helped!☺
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Which is equivalent?
attashe74 [19]

Answer:

the answer is -8

Step-by-step explanation:

4 0
3 years ago
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What is the inverse of the function f(x) = 2x + 1?|
padilas [110]

Answer:

1st option

Step-by-step explanation:

let y = f(x) and rearrange making x the subject

y = 2x + 1 ( subtract 1 from both sides )

y - 1 = 2x ( divide both sides by 2 )

\frac{y-1}{2} = x

Change y back into terms of x with x being the inverse h(x)

h(x) = \frac{x-1}{2} = \frac{1}{2} x - \frac{1}{2}

6 0
2 years ago
A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

5 0
2 years ago
in a circular garden the distance from the center of the circle to the edge is 15ft . If a gardner wants to plant roses in a 60
olya-2409 [2.1K]

Answer:

Approximately 117.81 ft²

Step-by-step explanation:

Find the area of the whole circle

A=πr²

A=π(15)²

A=706.86 ft²

Now you need to find the area of the garden covered in roses, so take the total degrees in a circle (360) and divide it by the degrees of the roses (60).

360/60=6

Take the area of the whole circle (706.86 ft²) and divide it by the number you just got (6). The number you get will be the area of the rose section.

706.86/6= 117.81 ft²

6 0
3 years ago
Given f(x)=-x-1, solve for x when f(x)=-10
Ilia_Sergeevich [38]

f(x) = -10

set the equation equal to -10 and solve for x:

-10 = -x-1

Add 1 to both sides:

-9 = -x

Divide both sides by -1:

x = 9

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2 years ago
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