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Artist 52 [7]
1 year ago
12

Find the mean of 25 numbers if the mean of 15 of them is 18 and the mean of the rest is 13

Mathematics
1 answer:
sergij07 [2.7K]1 year ago
7 0

Given the mean of 15 of them is 18 and the mean of the rest is 13

And the total numbers are 25

So,

First, we need to find the sum of all numbers

the mean of 15 of them is 18

so, the sum of the 15 numbers are = 18 * 15 = 270

The rest of the numbers = 25 - 15 = 10

the mean of the rest is 13

so, the sum of the rest = 13 * 10 = 130

so, the sum of all numbers = 270 + 130 = 400

so, the mean of the all numbers =

\frac{400}{25}=16

So, the answer is, mean = 16

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First, you need to find the average of the bases:

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Evaluate 2^2⋅4^3=<br><br>Your answer<br><br><br>​
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256

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3 years ago
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

Rounding up

A sample of 1068 is needed.

8 0
2 years ago
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