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Art [367]
1 year ago
15

Write an equation of the line with the given slope, m and y intercept (0,b) m=-6, b =-1/2 plss

Mathematics
1 answer:
Arlecino [84]1 year ago
5 0

Recall that an equation in slope-intercept form is as follows:

y=mx+b,

where m is the slope of the line, and (0,b) is the y-intercept.

Substituting m=-6, and b=-1/2 we get:

y=-6x+(-\frac{1}{2})\text{.}

Simplifying the above result we get:

y=-6x-\frac{1}{2}\text{.}

Answer:

y=-6x-\frac{1}{2}\text{.}

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Triangle LMN has L at (1, -1) and M at (2, 3). Triangle L'M'N' has L' at (-1, -1), M' at (3, -2), and N' is at (-3, 0). What are
fgiga [73]

Answer:

The answer is N(0,-3)

3 0
3 years ago
PLEASE HELP ALGEBRA 2 <br> Question is on the photo below
Sedbober [7]

Answer:

The value of f(x) - g(x) is:

f(x) - g(x) =  2x² + 6x - 4

Step-by-step explanation:

Given

f(x) = 3x² + x - 3

g(x) = x² - 5x + 1

To determine

f(x) - g(x)

Using the formula

f(x) - g(x) =  3x² + x - 3 - ( x² - 5x + 1)

              = 3x² + x - 3 - x² + 5x - 1

              = 2x² + 6x - 4

Therefore, the value of f(x) - g(x) is:

f(x) - g(x) =  2x² + 6x - 4

6 0
3 years ago
Ben is taking a typing class, and the following line graph represents the number of words per minute he was able to type each we
Crank
During week 2, he could type 15 words per minute, at his fourth week, he could type 30. So 30-15=15. He could type 15 words faster on week 4 than he could at week 2.
3 0
4 years ago
I NEED HELP PLEASE, THANKS! :)
Allushta [10]

Answer:  proof below

<u>Step-by-step explanation:</u>

Use the Difference formula for sin:

  sin (A - B) = sin(A)·cos(B) - cos(A)·sin(B)

sin (180° - θ) = sin(180°)·cos(θ) - cos(180°)·sin(θ)

                    =       0  · cos(θ)    -      -1  · sin(θ)

                    =              0           -           -sin(θ)

                    =                         + sin(θ)

sin (180° - θ) = sin(θ)  \checkmark

8 0
3 years ago
Read 2 more answers
Please help!!!!!!! How many inches would a point on the outer edge of the large gear travel in a 150º rotation? (The gear has a
damaskus [11]
In a full rotation, 360°, a point on the edge of a gear would travel a distance equal to its circumference.  The circumference of a circle is:

C=2πr, and since we are only traveling 150°, we need to set up an appropriate ratio for circumference to the distance the point travels:

d/C=150/360

d=5C/12 and since C=2πr

d=10πr/12

d=5πr/12, and since r=4in

d=5*4π/12 in

d=20π/12 in

d=5π/3 in

d≈5.24 in (to nearest hundredth of an inch)
4 0
3 years ago
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