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1 year ago

Write an equation of the line with the given slope, m and y intercept (0,b) m=-6, b =-1/2 plss

Mathematics

1 answer:

Arlecino [84]1 year ago

5 0

Recall that an equation in slope-intercept form is as follows:

$y=mx+b,$

where m is the slope of the line, and (0,b) is the y-intercept.

Substituting m=-6, and b=-1/2 we get:

$y=-6x+(-\frac{1}{2})\text{.}$

Simplifying the above result we get:

$y=-6x-\frac{1}{2}\text{.}$

Answer:

$y=-6x-\frac{1}{2}\text{.}$

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During which time period does Landon's elevation change the fastest? Explain how you know?

bogdanovich [222]

<h3>1. How many inches per minute does London's elevation change between 4 minutes and 8 minutes. </h3>

The question actually asks for the slope of the line that stands for the points $(4,3) \ and \ (8,6)$ why? because the questions tells us that London's elevation changes between 4 minutes and 8 minutes here. Hence, to find the slope of this line we have to use the following formula:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(4,3) \\ P(x_{2},y_{2})=P(8,6)$

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(4,3) \\ P(x_{2},y_{2})=P(8,6) \\ \\ So: \\ \\ m=\frac{6-3}{8-4}=0.75in/min$

<em>So London's elevation changes 0.75 inches per minute</em>

<h3>2. During which time period does London's elevation change the fastest?</h3>

The greater the absolute value of the slope of the line the faster London's elevation changes. Since this is a Piecewise function, we must analyze each period.

FIRST:

→ Between 0 minutes and 4 minutes the function is constant, so there is no any change here.

→ Between 10 minutes and 14 minutes the function is constant, so there is no any change here.

→ Between 18 minutes and 22 minutes the function is constant, so there is no any change here.

So the solution is not in these parts of the function.

SECOND:

→ Between 4 minutes and 10 minutes the function has a positive slope, so there is change here.

In the previous item we calculated the slope between 4 and 8 minutes that is the same slope between 4 and 8 minutes and equals 0.75.

→ Between 14 minutes and 18 minutes the function has a positive slope, so there is change here.

Let's take two points here, say, $(16,5) \ and \ (18,3)$

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\ \\ But: \\ \\ P(x_{1},y_{1})=P(16,5) \\ P(x_{2},y_{2})=P(18,3) \\ \\ So: \\ \\ m=\frac{3-5}{18-16}=-1 in/min$

As you can see, the absolute value here is 1 that is greater than 0.75.

<em>In conclusion, London's elevation changes the fastest between 14 and 18 minutes</em>

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3 years ago

Solve for y 3x+y=9 Chapter 5 cumulative review

Firdavs [7]

Answer:

y=-3x+9

Step-by-step explanation:

Just subtract -3x on both sides

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2 years ago

The parking lot at a store has a width of 20 yards 2 feet and the length of 30 yards. The cost to repave the parking lot is two

IceJOKER [234]

The cost to repave the parking lot is $912

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3 years ago

Read 2 more answers

g If the economy improves, a certain stock stock will have a return of 23.4 percent. If the economy declines, the stock will hav

dusya [7]

Answer:

$E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%$

Now we can find the second central moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965$

And the variance is given by:

$Var(X) = E(X^2) - [E(X)]^2$

And replacing we got:

$Var(X) = 413.5965 -(11.759)^2 =275.5105$

And finally the deviation would be:

$Sd(X) = \sqrt{275.5105}= 16.599 \%$

Step-by-step explanation:

We can define the random variable of interest X as the return from a stock and we know the following conditions:

$X_1 = 23.4 , P(X_1) =0.67$ represent the result if the economy improves

$X_2 = -11.9 , P(X_1) =0.33$ represent the result if we have a recession

We want to find the standard deviation for the returns on the stock. We need to begin finding the mean with this formula:

$E(X) = \sum_{i=1}^n X_i P(X_i)$

And replacing the data given we got:

$E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%$

Now we can find the second central moment with this formula:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965$

And the variance is given by:

$Var(X) = E(X^2) - [E(X)]^2$

And replacing we got:

$Var(X) = 413.5965 -(11.759)^2 =275.5105$

And finally the deviation would be:

$Sd(X) = \sqrt{275.5105}= 16.599 \%$

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3 years ago

What is the minimum number of x intercepts that a polynomial of degree 11 can? have?

stiks02 [169]

The degree of the polynomial will tell you the max amount of zeros you will have. 11 in this case.

However you can also have 9,7,5,3,1 (keep subtracting by 2)

So the answer is 1.

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3 years ago