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VashaNatasha [74]
3 years ago
11

HELP!!

Physics
1 answer:
Inga [223]3 years ago
3 0
The question gives you the formula to use, and then it gives you
the number to put into the formula.

-- Take the formula.

-- Write  8300  in place of ' D '.

-- Divide each side by  4.9 .

-- Take the square root of each side.

   Then it will say          (answer in seconds) = T  .
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A truck covers 40.0 m in 7.80 s while uniformly slowing down to a final velocity of 1.70 m/s. Please provide with explanation an
Karolina [17]

Answer:

a = -0.223 m/s

Explanation:

4 0
3 years ago
A permanent magnet is pushed into a wire, left there for a while, and then pulled out. During which time does a current run thou
lakkis [162]

Answer:

C. while the magnet is moving

Explanation:

Electromagnetic induction implies the production of electric current by mere movement of a magnet with respect to a coil or wire.

In the given question, current would be induced in the wire only when the magnet moves. That is either when the magnet is pushed into a wire, or when pulled out. But no current would flow through the wire when the magnet is left there for a while.

The current is induced because of the motion involved. Thus, the appropriate option is C.

8 0
3 years ago
Our galaxy is Select one: a. one member of a large cluster of thousands of galaxies. b. one member of a small cluster of galaxie
Art [367]

Answer:

the answer is b

5 0
3 years ago
What is the charge on an object that has 1.09x10^13 excess electrons?
Nadya [2.5K]

Answer:

-1.74\cdot 10^{-6} C

Explanation:

The electron is the particle that rotates around the nucleus of the atom; it has a negative electric charge equal to :

e=-1.6\cdot 10^{-19}C

which is known as fundamental charge.

For an object containing N excess electrons, the total charge of the object is

Q=Ne

In this problem, the number of excess electrons in the object is:

N=1.09\cdot 10^{13}

Therefore, by plugging it the numbers, we can find the value of Q, the total charge of the object:

Q=(1.09\cdot 10^{13})(-1.6\cdot 10^{-19})=-1.74\cdot 10^{-6} C

5 0
4 years ago
A stone is thrown vertically upward with a speed of 28.0 m/s how much time is required to reach this height
Solnce55 [7]
A stone is thrown vertically upward with a speed of 17.0 m/s. How fast is it moving when it reaches a height of 11.0 m? How long is required to reach this height?

Let’s review the 4 basic kinematic equations of motion for constant acceleration (this is a lesson – suggest you commit these to memory):

s = ut + ½ at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, we know u = 17.0m/s, a = -g = -9.81m/s^2, s = 11.0m and we want to know v and t, so from equation (2):

v^2 = u^2 + 2as

v^2 = 17.0^2 -2(9.81)(11.0)

v = √73.18 = 8.55m/s

now from equation (3):

v = u + at

8.55 = 17.0 – 9.81t

t = (8.55 – 17.0)/(-9.81) = 0.86s
6 0
3 years ago
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