Answer:
(a) 5.7 s
(b) 39 m/s
Explanation:
(a) u = 18 m/s
At the maximum height, the final velocity of ball is zero. lte teh time taken by the ball to go from 50 m height to maximum height is t.
use first equation of motion.
v = u + g t
0 = 18 - 10 x t
t = 1.8 s
Let the maximum height attained by the ball when it thrown from 50 m height is h'.
Use third equation of motion
v^2 = u^2 + 2 g h'
0 = 18^2 - 2 x 10 x h'
h' = 16.2 m
Total height from the ground H = h + h' = 50 + 16.2 = 76.2 m
Let t' be the time taken by the ball to hit the ground as it falls from maximum height.
use third equation of motion
H = ut + 1/2 x g t'^2
76.2 = 0 + 1/2 x 10 x t'^2
t' = 3.9 s
Total time taken by the ball to hit the ground = T = t + t' = 1.8 + 3.9 = 5.7 s
(b) Let v be the velocity with which the ball strikes the ground.
v^2 = u^2 + 2 g H
v^2 = 0 + 2 x 10 x 76.2
v = 39 m/s
Answer:
weight
Explanation:
weight is measurd in newtons (N)
As you move down a column :
* the atomic number increases
* the number of protims increases
* the atomic mass increases
* the electronegativity decreases
<h2>
Answer</h2>
The answer is 29495.3 kg
<h2>
Explanation</h2>
As we know, the Newton's Second Law of Motion
The F exerted by catapult = 9.35 * 
The Time is = 2.10 s
Velocity of the catapult = 240 km/h = 66.6 m/s (240*1000 m /3600 s)
The mass of jet = ?
First detrmine the acceleration as
{/tex}Acceleration = Velocity/Time {/tex}
Rearrange the formaula as
The mass will be 29495.3 kg
