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vampirchik [111]
3 years ago
10

A permanent magnet is pushed into a wire, left there for a while, and then pulled out. During which time does a current run thou

gh the wire? A from the time that the magnet is pushed into the coil to the time it is pulled out B while the magnet remains within the coil C while the magnet is moving D only while the magnet is being pulled out of the coil
Physics
1 answer:
lakkis [162]3 years ago
8 0

Answer:

C. while the magnet is moving

Explanation:

Electromagnetic induction implies the production of electric current by mere movement of a magnet with respect to a coil or wire.

In the given question, current would be induced in the wire only when the magnet moves. That is either when the magnet is pushed into a wire, or when pulled out. But no current would flow through the wire when the magnet is left there for a while.

The current is induced because of the motion involved. Thus, the appropriate option is C.

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A steel drill making 180 rpm is used to drill a hole in a block of steel. The mass of the steel block and the drill is 180 g. If
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Answer:

a) 37.8 W

b) 2 Nm

Explanation:

180 g = 0.18 kg

We can also convert 180 revolution per minute to standard angular velocity unit knowing that each revolution is 2π and 1 minute equals to 60 seconds

180 rpm = 180*2π/60 = 18.85 rad/s

We can use the heat specific equation to find the rate of heat exchange of the steel drill and block:

\dot{E} = mc\Delta \dot{t} = 0.18*420*0.5 = 37.8 J/s

Since the entire mechanical work is used up in producing heat, we can conclude that the rate of work is also 37.8 J/s, or 37.8 W

The torque T required to drill can be calculated using the work equation

E = T\theta

\dot{E} = T\dot{\theta} = T\omega

T = \frac{\dot{E}}{\omega} = \frac{37.8}{18.85} = 2 Nm

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3 years ago
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Professor Sanchez believes that children acquire language through reinforcement from adults, especially their parents. He believ
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Wood burning in a fire is what property
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4 years ago
Q1. In a 100m track event, the time taken by four runners is 10 sec., 10.2 sec., 10.4 sec and 10.6 sec. Find the ratio of their
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Distance (s)=100m
time
T₁=10
T₂=10.2
T₃=10.4
T₄=10.6
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V₂=\frac{100}{10.2}
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V₃=\frac{100}{10.4}
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V₄=\frac{100}{10.6}
V₄=9.43 m/s

V₁:V₂:V₃:V₄ = 10 : 9.8 : 9.61 : 9.43
8 0
3 years ago
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