Answer:
Step-by-step explanation:
6x - 5y = 15....... (1)
x=y+3..........(2)
Putting (2) in (1)
6(y + 3) - 5y = 15
6y + 18 - 5y = 15
6y - 5y = 15 - 18
y = -3
And x = y + 3
x = -3 + 3
x = 0
Answer:
Step-by-step explanation:
KE = ½mv²
KE₁₀ = ½(1100)10² = 55000 = 55 kJ
KE₃₀ = ½(1100)30² = 495000 = 495 kJ
9 times greater
X + y = 40.....multiply by -4
4x + 6y = 180
-------------------
-4x - 4y = -160 (result of multiplying by -4)
4x + 6y = 180
------------------add
2y = 20
y = 20/2
y = 10 <===
x = 30
Easy
f(g(1))
evaluate g(1) then plug thatin for x in f(x)
g(1)=(x+2)/3
g(1)=(1+2)/3
g(1)=1
f(g(1))=
f(1)=(1)^2+3(1)+6
f(1)=1+3+6
f(1)=10
f(g(1))=10
Answer:
What kind of problem? Multiplication? Division? What?
Step-by-step explanation: