Question

A 410 L volume of nitrogen gas is cooled from 61 C to -25 C. What is the volume of the nitrogen at the lower temperature if all volumes are measured at the same pressure?

Answer 1

Answer:

$304.5\text{L}$

Explanation:

Here, we want to get the volume of the nitrogen gas at the lower temperature

From Charles' law, we know that volume and temperature (in Kelvin) are directly proportion

The mathematical relationship is:

$\frac{V_1}{T_1}\text{ = }\frac{V_2}{T_2}$

Where:

V1 is the initial volume which is 410 L

V2 is the final volume which is unknown

T1 is the initial temperature which we will convert to Kelvin by adding 273.15 K, we have it as 61 + 273.15 = 334.15 K

T2 is the final temperature which we have to convert to Kelvin by adding it to 273.15K : We have that as -25 + 273.15 = 248.15 K

Substituting the values, we have it that:

$\begin{gathered} \frac{410}{334.15}\text{ = }\frac{V_2}{248.15} \\ \\ V_2\text{ = }\frac{248.15\text{ }\times410}{334.15} \\ \\ V_2\text{ = 304.5 L} \end{gathered}$