Answer:-
Explanations:- When the covalent bond is formed between two different atoms then the more electron negative atom has and the less electron negative atom has charge. More is the electron negativity difference, greater is the charge separation.
Looking at all the given molecules, Oxygen is most electron negative and hydrogen is less electron negative(hydrogen is more electron negative than Si). So, the best choice is .
Answer:
it is usually a restaurant that is located all over a certain country.
Answer:
4.9 x 10²²hockey pucks
Explanation:
Given parameters:
Number of moles of hockey = 0.0814moles
Unknown:
Number of pucks there = ?
Solution:
A mole of a substance is made up of Avogadro's number of particles.
Therefore;
1 mole of hockey pucks will contain 6.02 x 10²³ hockey pucks
0.0814 mole of hockey pucks will contain :
0.0814 x 6.02 x 10²³ = 4.9 x 10²²hockey pucks
Answer:
The particles in a liquid move very quickly due to heat while it is boiling and gradually turns to gas
2MnO4-(aq) + 16H+ + 10Cl-(aq) ⇔ 2Mn2+(aq) + 8H2O + 5Cl2 (g)
<h3>Further explanation</h3>
Given
Reaction(unbalanced)
Mno4- (aq) + Cl- (aq) → Mn2+ + Cl2 (g)
Required
Half reaction
Solution
1. Add coefficient(equalizing atoms in reaction)
2. Adding H₂O on the O-deficient side.
3. Adding H⁺ on the H-deficient side.
4. Adding e⁻
5. Equalizing the number of electrons and sum the all the half-reaction
1.MnO₄⁻(aq) = Mn²⁺(aq) reduction
2.MnO4(aq) = Mn2+(aq) + 4H2O
3. MnO4-(aq) + 8H+ = Mn2+(aq) + 4H2O
4. MnO4-(aq) + 8H+ + 5e- = Mn2+(aq) + 4H2O
Cl⁻(aq) = Cl₂(g) oxidation
1. 2Cl-(aq) = Cl2 (g)
2-3 none
4. 2Cl-(aq) = Cl2 (g) + 2e-
5.
MnO4-(aq) + 8H+ + 5e- = Mn2+(aq) + 4H2O x2
2Cl-(aq) = Cl2 (g) + 2e- x5
2MnO4-(aq) + 16H+ + 10e- = 2Mn2+(aq) + 8H2O
10Cl-(aq) = 5Cl2 (g) + 10e-
<em>2MnO4-(aq) + 16H+ + 10Cl-(aq) ⇔ 2Mn2+(aq) + 8H2O + 5Cl2 (g)</em>