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stira [4]
2 years ago
15

Which actions would the nurse implement when a client develops an anaphylactic reaction? select all that apply. one, some, or al

l responses may be correct.
Chemistry
1 answer:
spin [16.1K]2 years ago
3 0

The nurse would want to call a rapid response, place the patient on oxygen, and prepare for the administration of Epinephrine. This drug is the first-line treatment for anaphylactic shock. It will increase blood pressure, decrease swelling, and dilate the airway.

“Nursing is not an easy job. It takes physical and mental stamina to survive a 14-hour shift.” If you believe, you may find yourself thriving. in the midst of activity.

There is much to learn. The exams are difficult, the schedules are complex, and the challenges pile up. All these factors can make life as a student difficult. Nursing is a highly competitive field from the moment you start the application process until you graduate.

Learn more about nurses here

brainly.com/question/6685374

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Brainliest Available! Thank you in advance!
liraira [26]

Answer:

  3.0×10⁻¹³ M

Explanation:

The solubility product Ksp is the product of the concentrations of the ions involved. This relation can be used to find the solubility of interest.

<h3>Equation</h3>

The power of each concentration in the equation for Ksp is the coefficient of the species in the balanced equation.

  Ksp = [Al₃⁺³]×[OH⁻]³

<h3>Solving for [Al₃⁺³]</h3>

The initial concentration [OH⁻] is that in water, 10⁻⁷ M. The reaction equation tells us there are 3 OH ions for each Al₃ ion. If x is the concentration [Al₃⁺³], then the reaction increases the concentration [OH⁻] by 3x.

This means the solubility product equation is ...

  Ksp = x(10⁻⁷ +3x)³

For the given Ksp = 3×10⁻³⁴, we can estimate the value of x will be less than 10⁻⁸. This means the sum will be dominated by the 10⁻⁷ term, and we can figure x from ...

  3.0×10⁻³⁴ = x(10⁻⁷)³

Then x = [Al₃⁺³] will be ...

  [\text{Al}_3^{\,+3}]=\dfrac{3.0\times10^{-34}}{10^{-21}}\approx \boxed{3.0\times10^{-13}\qquad\text{moles per liter}}

We note this value is significantly less than 10⁻⁷, so our assumption that it could be neglected in the original Ksp equation is substantiated.

__

<em>Additional comment</em>

The attachment shows the solution of the 4th-degree Ksp equation in x. The only positive real root (on the bottom line) rounds to 3.0×10^-13.

6 0
1 year ago
Read 2 more answers
PLS HELP ASAP i really need an answer a correct one
nata0808 [166]

Answer: 67.23 L

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Putting in the values we get:

\text{Number of moles of methane}=\frac{48g}{16g/mol}=3moles

1 mole of methane occupies = 22.4 L

Thus 3 moles of methane occupy = \frac{22.4}{1}\times 3=67.23L

Thus volume of 48 grams of methane gas is 67.23 L

6 0
3 years ago
) How many molecules are in 23 moles of Sodium?
densk [106]
4)<span>1.24⋅<span>1024</span></span><span> formula units

</span>1 mole Na<span> (sodium)</span>
6 0
3 years ago
If you are given 1.709 moles of solute, and you dilute it to make 2.10 liters of solution, what is the resulting molarity (M)? (
azamat
Moles/MxL 

1.709moles/2.10L =<span>0.814M</span>
4 0
3 years ago
How many moles of calcium chloride, cacl2, can be added to 1.5 l of 0.020 m potassium sulfate, k2so4, before a precipitate is ex
Brut [27]
When CaSO4 → Ca2+ + SO4
So when we have Ksp = [Ca2+][SO4]

when Ksp = 4.93 x 10^-5
and [SO4] = 0.02 M 
so by substitution we can get [Ca2+] 
4.93x10^-5 = [Ca2+] [0.02]
∴ [Ca2+] = 0.0025 mol/L

∴ the moles of calcium chloride = 0.0025 mol / L * 1.5 L
                                                      = 0.00167 mol

4 0
3 years ago
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