Question

Assume that an int variable age has been declared and already given a value. Assume further that the user has just been presented with the following menu:
S: hangar steak, red potatoes, asparagus
T: whole trout, long rice, brussel sprouts
B: cheddar cheeseburger, steak fries, cole slaw
(Yes, this menu really IS a menu!)
Write some code that reads the String (S or T or B) that the user types in into a String variable choice that has already been declared and prints out a recommended accompanying drink as follows: if the value of age is 21 or lower, the recommendation is "vegetable juice" for steak, "cranberry juice" for trout, and "soda" for the burger. Otherwise, the recommendations are "cabernet", "chardonnay", and "IPA" for steak, trout, and burger respectively. Regardless of the value of age, your code should print "invalid menu selection" if the character read into choice was not S or T or B.
ASSUME the availability of a variable, stdin, that references a Scanner object associated with standard input.
Instructor Notes:
Hint:

Use .equals for String comparison, e.g.
if (choice.equals("B")) instead of
if (choice == "B") // BAD

You might want to skip this one and do section 3.6 (which covers String comparison) beforehand.

Answer 1

Using the knowledge of computational language in C++ it is possible to write a code that assume that an int variable age has been declared and already given a value

Writting the code:

#include<stdio.h>

#include<conio.h>

int main()

{

//variables to rad choice and age

char choice;

int age;

//read age and choice

printf("\tEnter your age: ");

scanf("%d", &age);

//fflush the keyboard buffer before reading choice

fflush(stdin);

printf("\tEnter your choice: ");

scanf("%c", &choice);

//print the invalid message if the choice is otherthan the S,T,B

if(choice!='S' && choice !='T' && choice !='B')

{

printf("Invalid menu choice");

getch();

}

else if (age <22)

{

if (choice =='S')

{

printf("\tvegetable juice");

}

else if (choice =='T')

{

printf("\tcranberry juice");

}

else if (choice == 'B')

{

printf("\tsoda");

}

}

else

{

if (choice == 'S')

{

printf("\tcabernet");

}

else if (choice =='T')

{

printf("\tchardonnay");

}

else if (choice == 'B')

{

printf("\tIPA");

}

}

//pause the console output until user press any key on keyboard

getch();

}

See more about C++ at brainly.com/question/19705654

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