Ask question

Ask question

All categories

2 years ago

9

Alberto has 2 cats the smaller cat weighs 10 3/4 pounds the larger cat weighs 15 1/3 pounds how much do the cats weigh altogethe

r A. 26 1/12 B. 26 11/12 C. 25 4/7 D. 25 7/12

1 answer:

ElenaW [278]2 years ago

4 0

Answer:

A. 26 1/2

Step-by-step explanation:

change denominator so they can be the same

3/4*3 = 9/12

1/3*4 = 4/12

Add the whole numbers : 10 +15=25

9/12+4/12= 13/12 so 1 1/12

26 1/12

You might be interested in

PLS HELP ME ASAP I DONT HAVE TIME. IT ALSO DETECTS IF ITs RIGHT OR WRONG.

grin007 [14]

Answer:

It should be 9 m :)

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Y''+y'+y=0, y(0)=1, y'(0)=0

mars1129 [50]

Answer:

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Step-by-step explanation:

A second order linear , homogeneous ordinary differential equation has form $ay''+by'+cy=0$ .

Given: $y''+y'+y=0$

Let $y=e^{rt}$ be it's solution.

We get,

$\left ( r^2+r+1 \right )e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2+r+1=0$

{ we know that for equation $ax^2+bx+c=0$ , roots are of form $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ }

We get,

$y=\frac{-1\pm \sqrt{1^2-4}}{2}=\frac{-1\pm \sqrt{3}i}{2}$

For two complex roots $r_1=\alpha +i\beta \,,\,r_2=\alpha -i\beta$ , the general solution is of form $y=e^{\alpha t}\left ( c_1\cos \beta t+c_2\sin \beta t \right )$

i.e $y=e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

Applying conditions y(0)=1 on $e^{\frac{-t}{2}}\left ( c_1\cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$ , $c_1=1$

So, equation becomes $y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

On differentiating with respect to t, we get

$y'=\frac{-1}{2}e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+c_2\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )+e^{\frac{-t}{2}}\left ( \frac{-\sqrt{3}}{2} \sin \left ( \frac{\sqrt{3}t}{2} \right )+c_2\frac{\sqrt{3}}{2}\cos\left ( \frac{\sqrt{3}t}{2} \right )\right )$

Applying condition: y'(0)=0, we get $0=\frac{-1}{2}+\frac{\sqrt{3}}{2}c_2\Rightarrow c_2=\frac{1}{\sqrt{3}}$

Therefore,

$y=e^{\frac{-t}{2}}\left ( \cos\left ( \frac{\sqrt{3}t}{2} \right )+\frac{1}{\sqrt{3}}\sin \left ( \frac{\sqrt{3}t}{2} \right ) \right )$

3 0

2 years ago

The sequence follows a minus 3 pattern: 12, 9, 6, 3, ....

hram777 [196]

X times -3= a
i think thats it

3 0

3 years ago

What is (-4x² + 3x + 3)(x² - 2x + 2) as a polynomial

gizmo_the_mogwai [7]

The given expression is in the form of the polynomial as -4x⁴+11x³-5x²+6 and the degree of the polynomial is 4.

<h3>What is a polynomial?</h3>

Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.

$\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n$

It is given that the polynomial expression is, (-4x² + 3x + 3)(x² - 2x + 2)

We have to simplify the expression by multiplying the expression as,

=-4x²(x² - 2x + 2)+3x(x² - 2x + 2)+3(x² - 2x + 2)

=-4x⁴+8x³-8x²+3x³-6x²+6x+3x²-6x+6

= -4x⁴+11x³-5x²+6

Thus, the given expression is in the form of the polynomial as -4x⁴+11x³-5x²+6 and the degree of the polynomial is 4.

Learn more about Polynomial here:

brainly.com/question/17822016

#SPJ1

5 0

1 year ago

What is 10 to the second power?

allochka39001 [22]

It would be 10x10 =100 or in other word 10 times itself. Also known as 10 with the 2 hanging over the 10.

3 0

2 years ago

Read 2 more answers