Answer:
Half the age of Carlos four years ago is 2 years more than one-third his current age.
Step-by-step explanation:
We want to write a word problem for the equation.
Let x represent the present age of Carlos.
Four years ago, Carlos was x-4 years.
Half his age four years ago is ½(x-4)
Two years more than one-third his current age is ⅓x+2
Answer:
.0006
Step-by-step explanation:
I'm not sure if this is correct.. sorry if this is wrong.. :(
Answer:
Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.
The total cost of both games is:
X + Y
We know that both games cost just above AED 80
Then:
X + Y > AED 80
From this, we want to prove that at least one of the games costed more than AED 40.
Now let's play with the possible prices of X, there are two possible cases:
X is larger than AED 40
X is equal to or smaller than AED 40.
If X is more than AED 40, then we have a game that costed more than AED 40.
If X is less than or equal to AED 40, then:
X ≥ AED 40
Now let's take the maximum value of X in this scenario, this is:
X = AED 40
Replacing this in the first inequality, we get:
X + Y > AED 80
Replacing the value of X we get:
AED 40 + Y > AED 80
Y > AED 80 - AED 40
Y > AED 40
So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.
So we proven that in all the possible cases, at least one of the two games costs more than AED 40.
If you have zero dollars you can’t buy anything
This is a linear equation y = mx, where:
m= slope or reading rate:
x = the number of minutes
y = the number of pages read.
So the equation becomes: y = 4.5.x
How many minutes it will take to read 90 pages (y):
90 = 4.5.x or x = 90/4.5 and x = 20 minutes
So the ordered pair will be (20,90)
