Solve the equation, justify<br> each step with an algebraic<br> property.<br> 7 = 16 + 3x

A taxicab charges $3.00 per person

Delicious77 [7]

Answer:

I believe the answer would be 20 miles max for one passenger.

Step-by-step explanation:

This is because if you create an equation out of this, knowing that only one passenger will be riding, you will get:

$3.00+$1.25x=$28 ($3 added too $1.25 times the number of miles (x) which equals the total amount you have ($28)).

x being the number of miles (so we need to calculate for x)

$3 + $1.25x = $28

-subtract 3 on both sides-

$1.25x=$28-$3

$1.25x=$25

-divide by 1.25 on both sides-

x=$25/$1.25

x=20 miles

Not sure if all calculations are correct, but I hope this helps :)!

6 0

2 years ago

What is the factored form of 24x2 + 52% – 207

dlinn [17]

The answer is -3962/25

4 0

2 years ago

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

Lapatulllka [165]

Answer:

Step-by-step explanation:

Given that there is a function of x,

$f(x) = 2sin x + 2cos x,0\leq x\leq 2\pi$

Let us find first and second derivative for f(x)

$f'(x) = 2cosx -2sinx\\f"(x) = -2sinx-2cosx$

When f'(x) =0 we have tanx = 1 and hence

a) f'(x) >0 for I and III quadrant

Hence increasing in $(0, \pi/2) U(\pi,3\pi/2)\\$

and decreasing in $(\pi/2, \pi)U(3\pi/2,2\pi)$

$x=\frac{\pi}{4}, \frac{3\pi}{4}$

$f"(\pi/4)$

Hence f has a maxima at x = pi/4 and minima at x = 3pi/4

b) Maximum value = $2sin \pi/4+2cos \pi/4 =2\sqrt{2}$

Minimum value = $2sin 3\pi/4+2cos 3\pi/4 =-2\sqrt{2}$

c)

f"(x) =0 gives tanx =-1

$x= 3\pi/4, 7\pi/4$

are points of inflection.

concave up in (3pi/4,7pi/4)

and concave down in (0,3pi/4)U(7pi/4,2pi)

3 0

2 years ago

Can someone please simplify the complex fraction?

dmitriy555 [2]

$\bf \cfrac{\qquad \frac{x+3}{4x^2-16}\qquad }{\frac{2x^2+10x+12}{2x-4}}\implies \cfrac{\frac{x+3}{4(x^2-4)}}{\frac{\underline{2}(x^2+5x+6)}{\underline{2}(x-2)}}\implies \cfrac{\frac{x+3}{4(x^2-2^2)}}{\frac{x^2+5x+6}{x-2}}\implies \cfrac{\frac{x+3}{4(x-2)(x+2)}}{\frac{(x+3)(x+2)}{x-2}}$

$\bf \cfrac{\underline{x+3}}{4\underline{(x-2)}(x+2)}\cdot \cfrac{\underline{x-2}}{\underline{(x+3)}(x+2)}\implies \cfrac{1}{4(x+2)}\cdot \cfrac{1}{x+2}
\\\\\\
\cfrac{1}{4(x+2)(x+2)}\implies \cfrac{1}{4(x^2+4x+4)}\implies \cfrac{1}{4x^2+16x+16}$

8 0

2 years ago

A sector of a circle of radius 80 mi has an area of 1600 mi2. Find the central angle (in radians) of the sector.

Butoxors [25]

Answer:

The central angle of the sector is 0.5 radian

Step-by-step explanation:

given;

radius of the circle, r = 80 mi

area of the sector, A = 1600 mi²

Area of sector is given by;

A = ¹/₂r²θ

where;

θ is the central angle (in radians) of the sector

$\theta = \frac{2A}{r^2}\\\\\theta = \frac{2*1600}{80^2}\\\\ \theta = 0.5 \ radian$

Therefore, the central angle of the sector is 0.5 radian

3 0

2 years ago

Solve the equation, justify each step with an algebraic property. 7 = 16 + 3x