use one five dollar box then use 4 4 $ boxes then its five dollar boxes the rest of the way so it would be 59 5$ boxes then Four 4$ boxes
I think your question isn’t phrased well
Answer:
75 less student tickets than adult tickets. The total is 625 tickets. So the student and adult tickets have to equal 625 when added.
Step-by-step explanation:
Student tickets: 275
Adult tickets: 350
B^2 - 4ac > 0
2x^2 +7x -1 =0
b =7 a=2 c= -1
b^2 - 4ac = 7^2 - 4*2*(-1)
= 49 + 8
= 57
Hello!
(4y + 8) - (7y - 12) = 11 is 1(4y + 8) - 1(7y - 12) = 11
1(4y + 8) - 1(7y - 12) = 11 Given
4y + 8 - 7y + 12 = 11 Distribute the 1 and the -1
-3y + 20 = 11 Combine like terms
-3y = -9 Subtract 20 from both sides
y = 3 Divide both sides by -3
Answer:
y = 3
