We have the following limit:
(8n2 + 5n + 2) / (3 + 2n)
Evaluating for n = inf we have:
(8 (inf) 2 + 5 (inf) + 2) / (3 + 2 (inf))
(inf) / (inf)
We observe that we have an indetermination, which we must resolve.
Applying L'hopital we have:
(8n2 + 5n + 2) '/ (3 + 2n)'
(16n + 5) / (2)
Evaluating again for n = inf:
(16 (inf) + 5) / (2) = inf
Therefore, the limit tends to infinity.
Answer:
d.limit does not exist
Answer: You would have 4160$
Step-by-step explanation: there is 52 weeks in a year so 52 times 80
The selected answer is correct
Answer:
x = -3
Step by step explaination-
3(2(-3) + 4) = -6
Answer:
<em>y=2 cos (π/4x-π/4)</em>
Step-by-step explanation:
<em>Given</em>
<em>A cosine function has an amplitude of 2, a midline of 5 and a period of 8.</em>
<em>To find: </em>
<em>A cosine function.</em>
<em>Explanation:</em>
<em>Let the function be,</em>
<em></em>
<em>Since amplitude is 2.</em>
<em>Then,</em>
<em></em>
<em>Also, since the period is 8.</em>
<em>Then,</em>
<em></em>

<em>And, since midline is 5.</em>
<em>Hence, the cosine function is,</em>
<em>y=2 cos (</em>
<em>x-</em>
<em></em>