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3 years ago

12

What is the midpoint of OA ?

1 answer:

liraira [26]3 years ago

7 0

Answer:

(m,n)

Step-by-step explanation:

Since O is at the origin, we can take the coordinates of point A and divide them by 2 to find the midpoint

( 2m/2,2n/2)

The midpoint is at (m,n)

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I will give you 100 points HELp

Naddika [18.5K]

Answer:

CD ≈ 26.0 cm

Step-by-step explanation:

using the sine ratio in right triangle ABD

sin35° = $\frac{opposite}{hypotenuse}$ = $\frac{AB}{BD}$ = $\frac{12}{BD}$ ( multiply both sides by BD )

BD × sin35° = 12 ( divide both sides by sin35° )

BD = $\frac{12}{sin35}$ ≈ 20.92 cm

using the sine rule in Δ BCD

$\frac{BD}{sinC}$ = $\frac{CD}{sinB}$ , that is

$\frac{20.92}{sin52}$ = $\frac{CD}{sin102}$ ( cross- multiply )

CD × sin52° = 20.92 × sin102° ( divide both sides by sin52° )

CD = $\frac{20.92sin102}{sin52}$ ≈ 26.0 cm ( to 3 significant figures )

6 0

2 years ago

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Which is faster 80km/h or 60 mi/h and why?

Vlada [557]

80km/h because km is more than miles

8 0

2 years ago

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Whay percent of 25 is 12?

Tcecarenko [31]

Answer:

48% of 25 is 12.

Step-by-step explanation:

To find : what percent of 25 is 12?

Solution : Let x be the percentage of 25 which is 12

So, by the statement

x% of 25 = 12

Now, we have to calculate the value of x

Step 1- Write the expression

$\frac{x}{100} \times 25 = 12$

Step 2- divide 25 by 100

$\frac{x}{4} = 12$

Step 3- Cross multiply

$x=48$

Therefore, 48% of 25 is 12.

7 0

3 years ago

A farmer takes 1 day to fill 7 bins of corn. At this rate, how long will it take to fill 560 bins?

Jlenok [28]

It will take him 80 days

5 0

2 years ago

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Fred walked a trail at 2 mph. Paul started 30 minutes later on the same trail and walked at a pace of 3 mph. Create a system of

spayn [35]

Answer:

$y=2x\\y=3(x-\frac{1}{2})$

Paul will catch Fred after $1\ hours$ at a distance $3\ miles$ .

Step-by-step explanation:

Distance is represented by $y$ and the time is represented by $x$ . Here after $x$ hours(when Fred started) the distance covered by Fred and Paul is same that is $y$ .

For Fred:

time= $x$

distance= $y$

Speed $=2\ mph$

$Distance=speed\times time\\y=2\times x \\y=2x$

Paul:

Since Fred started 30 minutes earlier, so Paul's travel time will be 30 minutes less than that of Fred.

Time $=x-\frac{1}{2}$

Speed $=3\ mph$

Distance $=y\\$

$y=3\times (x-\frac{1}{2})\\y=3(x-\frac{1}{2})$

Hence system of equation

$y=2x\\y=3(x-\frac{1}{2})$

Solution of this system of equations gives the time, when Paul will catch Fred and distance covered by each of them.

$y=2x\\y=3(x-\frac{1}{2})\\\\2x=3x-\frac{3}{2}\\x=\frac{3}{2}\\\\y=2x\\y=2\times \frac{3}{2}\\y=3$

Time taken by Paul $=x-\frac{1}{2}=\frac{3}{2}-\frac{1}{2}=1$

Hence Paul will catch Fred after $1\ hours$ at a distance $3\ miles$ .

3 0

2 years ago