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Softa [21]
1 year ago
15

a solid object is found to weigh 4.784.78n in air. when it is weighed while fully immersed in water, its apparent weight is 2.48

2.48n. what is the density of the object?
Physics
1 answer:
ololo11 [35]1 year ago
3 0

A solid object is found to weigh 4.784.78n in air. when it is weighed while fully immersed in water, its apparent weight is 2.482.48n. 983 is the density of the object.

The substance's density is defined as its mass per unit of volume (volumetric mass density or specific mass). Although the Latin letter D may also be used, the symbol for density that is most usually used is (the lower case Greek letter rho). where V is the volume, is the density, and m is the mass. Weight per unit volume is a common informal definition of density, however this is incorrect scientifically; the actual term is specific weight. The US oil and gas industry serves as one illustration of this. A pure substance's mass concentration in numbers is equal to its density. To make density comparisons between different systems of units easier, it is occasionally replaced by the dimensionless quantity "relative density" or "specific gravity," which is the ratio of the density of the material to that of a standard material, usually water. If a substance's relative density to water is less than one, it will float in it. Temperature and pressure have an impact on a substance's density. This variation is frequently not very noticeable for solids and liquids, but it is very noticeable for gases. As pressure is applied, an object's density rises, which reduces the object's volume. With a few rare exceptions, as temperature increases, a substance's density decreases as its volume grows.

To know more about density please refer: brainly.com/question/15164682

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A constant horizontal force F is applied to a 5 kg box on a frictionless horizontal surface. The box starts from rest and moves
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3 years ago
Heavy crate sits at rest on the floor of a warehouse. you push on the crate with a force of 400 n, and it doesn't budge. what is
maks197457 [2]

Heavy crate sits at rest on the floor of a warehouse. you push on the crate with a force of 400 N, and it doesn't budge. The magnitude of the friction force on the crate in Newton is 400N

This is due to Friction force, which is defined as the resisting force that acts on a body when it is at rest (Static friction) or when it is in motion (Kinetic friction).

When a force is applied on a stationary body, the force of static friction starts to act on the body which prevents any relative motion between the object and surface. The magnitude of friction increases up to μsN, where μs is the coefficient of static friction. As the crate didn't budge, it means the amount of force applied was less than μsN. Hence the force applied was canceled by an equal and opposite amount of frictional force which was equal to 400N.

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8 0
2 years ago
What's the velocity for each trial? <br> And what's the average velocity?
adelina 88 [10]
Since each time trial is the same the average will be the direct answer, and the formula for velocity is distance divided by time, therefore it will come out to, 1.92307692. Whatever your teacher what the rounding process to be will vary but the straight up answer is there.
5 0
3 years ago
A box is held at rest by two ropes that form 30° angles with the vertical. The tension T in either rope is 42 N. What is the wei
iragen [17]
<h3><u>Answer;</u></h3>

= 73 N

<h3><u>Explanation</u>;</h3>

Using the formula

2 T cos(30°) = w

Where; T is the tension on each string, while w is the weight of the box given by mg

Therefore;

W = 2Tcos 30°

    = 2 × 42 cos 30°

    = 84 cos 30°

    = 72.74

<u>   ≈ 73 N</u>

7 0
4 years ago
A rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. Calculate the normal force (in N) acting on an a
goldenfox [79]

According to Newton's 3rd law, there will be equal and opposite force on the astronaut which is  -6048 N

<h3>What does Newton's third law say ?</h3>

The law state that in every action, there will be equal and opposite reaction.

Given that a rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. We are to calculate the normal force (in N) acting on an astronaut of mass 87.4 kg, including his space suit.

Let us first calculate the force involved in the acceleration of the rocket by using the formula

F = ma

Where mass m = 87.4 kg, acceleration a = 69.2 m/s2

Substitute the two parameters into the formula

F = 87.4 x 69.2

F = 6048.08 N

According to the Newton's 3rd law, there will be equal and opposite force on the astronaut.

Therefore, the normal force acting on the astronaut is -6048 N approximately

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7 0
2 years ago
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