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3 years ago

The moving charge in the wire causes the compass to deflect; this is because

Physics

2 answers:

Marta_Voda [28]3 years ago

6 0

Answer:

The moving charge induces a magnetic field

Explanation:

According to Faraday's Law, the moving charges in a closed circuit (conductor) induces a magnetic field.

There is a potencial difference called electromotive force, wich is proportional to the magnetic flux through a surface. Matematically this coud be written as

$\epsilon = -\frac{d\Phi}{dt}$

where $\epsilon$ is the EMF, and $\Phi$ is the magnetic flux (the derivative on t means that the magnetic flux is changing in time).

This means that the moving charges, generates an EMF that is proportional to the magnetic flux change.

Therefore, A is the correct answer.

JulijaS [17]3 years ago

5 0

The answer is A. the moving charge induces a magnet field .

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You're in a car that gets 28 miles per gallon of gas, driving it at a constant speed. If you took the gas from the car tank, and

Nataly [62]

Answer:

The diameter of the hose is 0.326 mm.

Explanation:

Given that,

Speed of car = 28 miles/galllon

We need to calculate the radius

The rate of flow of fluid is from the equation of continuity

$\dfrac{V}{t}=Av$

Where, A = area of cross sectional

$\dfrac{V}{t}=\pi r^2v$

We know that,

The velocity is the ratio of displacement of gas per unit time.

$\dfrac{V}{t}=\pi r^\dfrac{x}{t}$

$\dfrac{V}{x}=\pi r^2$

Put the value into the formula

$\dfrac{0.00378541}{28\times1609.34}=\pi r^2$

$r=\sqrt{\dfrac{0.00378541}{28\times1609.34\times\pi}}$

$r=1.63\times10^{-4}\ m$

We need to calculate the diameter of the hose

$d = 2r$

Put the value of r

$d=2\times1.63\times10^{-4}$

$d=0.326\ mm$

Hence, The diameter of the hose is 0.326 mm.

6 0

3 years ago

Two gratings A and B have slit separations dA and dB, respectively. They are used with the same light and the same observation s

77julia77 [94]

Answer:

a) dB / dA = 2 ,

b) Network B Network A

2 1

4 2

6 3

Explanation:

a) The expression for grating diffraction is

d sin θ = m λ

where d the distance between two slits, λ the wavelength and m an integer that represents the diffraction range

In this exercise we are told that the two spectra are in the same position, let's write the expression for each network

Network A

m = 1

sin θ = 1 λ / dA

Network B

m = 2

sin θ = 2 λ / dB

they ask us for the relationship between the distances, we match the equations

λ / dA) = 2 λ / dB

dB / dA = 2

b) let's write the equation of the networks

sin θ = m_A λ / dA

sin θ = m_B λ / dB

we equalize

m_A λ/ dA = m_B λ / dB

we use that

dB / dA = 2

m_A 2 = m_B

therefore the overlapping orders are

Network B Network A

2 1

4 2

6 3

4 0

3 years ago

Two stones are dropped from the edge of a 60m cliff , the second stone 1.6secon after the first . How far below the top of the c

tigry1 [53]

Answer:

The separation between the two stones is 36 m, when the second stone is approximately 10.9 m below the top of the cliff

Explanation:

The given parameters are;

The height of the cliff from which the stones are dropped, h = 60 m

The time at which the second stone is dropped = 1.6 seconds after the first

The distance below the top of the cliff when the distance between the two stones is 36 m = Required

We have;

The kinematic equation of motion that can be used is s = u·t - (1/2)·g·t²

For the first stone, we have, s₁ = u·t₁ - (1/2)·g·t₁²

For the second stone, we get; s₂ = u·t₂ - (1/2)·g·t₂²

t₁ = t₂ + 1.6

g = The acceleration due to gravity ≈ 9.81 m/s²

s = The distance below the cliff top

The initial velocity of the stones, u = 0

Let t represent the time from which the second stone is dropped at which the distance between the two stones is 36 m, we have;

s₁ = u·(t + 1.6) + (1/2)·g·(t + 1.6)²

s₂ = u·t + (1/2)·g·t²

u = 0

∴ s₁ - s₂ = 36 = (1/2)·g·(t + 1.6)² - (1/2)·g·t²

2 × 36/(g) = (t + 1.6)² - t² = t² + 3.2·t + 2.56 - t² = 3.2·t + 2.56

2 × 36/(9.81) = 3.2·t + 2.56

t = (2 × 36/(9.81) - 2.56)/3.2 = ≈ 1.49 s

t ≈ 1.49 s

s₂ = (1/2)·g·t²

∴ s₂ = (1/2) × 9.81 × 1.49² ≈ 10.9

The distance below the top of the cliff of the second stone when the the separation between the two stones is 36 m, s₂ ≈ 10.9 m.

5 0

3 years ago

What force must the people overcome in order to lift the rock? (rock on one end and two guys on the other end)

KATRIN_1 [288]

I think it is gravity

5 0

4 years ago

An engine absorbs 1.69 kJ from a hot reservoir at 277°C and expels 1.25 kJ to a cold reservoir at 27°C in each cycle.

Anna35 [415]

Answer

Given,

Energy absorbed, $Q_H = 1.69\ kJ$

Energy expels, $Q_C = 1.25\ kJ$

Temperature of cold reservoir, T = 27°C

a) Efficiency of engine

$\eta = \dfrac{Q_H - Q_C}{Q_H}\times 100$

$\eta = \dfrac{1.69 - 1.25}{1.69}\times 100$

$\eta =26.03 %$

b) Work done by the engine

$W = Q_H- Q_C$

$W =1.69 - 1.25$

$W = 0.44\ kJ$

c) Power output

t = 0.296 s

$P = \dfrac{W}{t}$

$P = \dfrac{0.44}{0.296}$

$P = 1.486\ kW$

8 0

3 years ago