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Sloan [31]
3 years ago
13

A spring has a spring constant of 113 N/m . How much elastic potential energy is stored in the spring when it is compressed by 0

.03 m?A:0.23 j B:0.022 j C:0.051 j D: 1.70 j
Physics
2 answers:
andrezito [222]3 years ago
7 0

Answer:

= 1.7 Joules

Explanation:

The electrical potential energy is given by;

P.E = 1/2 ke²

Where, k is the spring constant, e is the extension

Therefore;

Electrical potential energy = 1/2 × 113 N/m × 0.03 m

                                           =  1.695 Joules

                                           <u>= 1.7 J</u>

Alexus [3.1K]3 years ago
4 0

Answer:

0.051 J

Explanation:

K = 113 N/m

y = 0.03 m

The elastic potential energy of the system is given by

U = 1/2 K y^2 = 0.5 x 113 x 0.03 x 0.03 = 0.051 J

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zhenek [66]

Answer:

0.1 m

Explanation:

F = Force exerted on spring = 3 N

k = Spring constant = 60 N/m

x = Displacement of the block

As the energy of the system is conserved we have

Fx=\dfrac{1}{2}kx^2

\\\Rightarrow x=\dfrac{2F}{k}

\\\Rightarrow x=\dfrac{2\times 3}{60}

\\\Rightarrow x=0.1\ m

The position of the block is 0.1 from the initial position.

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3 years ago
A 4-kg toy car with a speed of 5 m/s collides head-on with a stationary 1-kg car. After the collision, the cars are locked toget
mihalych1998 [28]

Kinetic energy lost in collision is 10 J.

<u>Explanation:</u>

Given,

Mass, m_{1} = 4 kg

Speed, v_{1} = 5 m/s

m_{2} = 1 kg

v_{2} = 0

Speed after collision = 4 m/s

Kinetic energy lost, K×E = ?

During collision, momentum is conserved.

Before collision, the kinetic energy is

\frac{1}{2} m1 (v1)^2 + \frac{1}{2} m2(v2)^2

By plugging in the values we get,

KE = \frac{1}{2} * 4 * (5)^2 + \frac{1}{2} * 1 * (0)^2\\\\KE = \frac{1}{2} * 4 * 25 + 0\\\\

K×E = 50 J

Therefore, kinetic energy before collision is 50 J

Kinetic energy after collision:

KE = \frac{1}{2} (4 + 1) * (4)^2 + KE(lost)

KE = 40J + KE(lost)

Since,

Initial Kinetic energy = Final kinetic energy

50 J = 40 J + K×E(lost)

K×E(lost) = 50 J - 40 J

K×E(lost) = 10 J

Therefore, kinetic energy lost in collision is 10 J.

4 0
4 years ago
If an object has a fast velocity, the dots on a ticker tape diagram will be _____.
Gala2k [10]

Answer:

If an object has a fast velocity, the dots on a ticker tape diagram will be far apart.

7 0
3 years ago
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Svetradugi [14.3K]

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Two 0.50 g spheres are charged equally and placed 2.5 cm apart. When released, they begin to accelerate at 170 m/s^2 .What is th
vitfil [10]

Answer:

q=7.65*10^{-8}C

Explanation:

Using Newton's second law, we calculate the magnitude of the electric force between the spheres:

F=ma\\F=0.5*10^{-3}kg(170\frac{m}{s^2})\\F=0.085N

The magnitude of the charge in both spheres is the same. So, we calculate the charge, using Coulomb's law:

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