All categories

1 year ago

Solve for v. 13v=9v+12 3 Simplify your answer as much as possible.

Mathematics

1 answer:

salantis [7]1 year ago

4 0

Answer:

X=3

Step-by-step explanation:

1-move the (9v) to the other side and change it to negative and it will be (13v-9v=12)

2-Collect like terms and it will be (4v=12)

3-Divide both sides on 4 and it will be (v=3)

You might be interested in

PLEASE ANSWER FAST MARKING BRAINLIEST!

NikAS [45]

Answer:

13/20

Step-by-step explanation:

P ( jacket ) =number of jackets/ total

= 13/ 20

7 0

3 years ago

In the following alphanumeric series, what letter comes next? V Q M J H

Daniel [21]

Hola mate

here is your answer

Heyyyy dude

hope it help you

5 0

3 years ago

What are the coordinates of the point on the directed line segment from (−6,8) to (6,−7) that partitions the segment into a rati

Maslowich

Answer:

(2, -2)

Step-by-step explanation:

The difference of coordinates is ...

(6, -7) -(-6, 8) = (12, -15)

The point of interest is located 2/(2+1) = 2/3 of this distance from the first point. So, the point of interest is ...

first point + 2/3 distance

= (-6, 8) + (2/3)(12, -15)

= (-6, 8) + (8, -10)

= (2, -2)

_____

In symbolic terms, the point P that is 2/3 of the distance from A to B is ...

P = A + (2/3)(B -A) = (1/3)A +(2/3)B

P = (A +2B)/3

Filling in the coordinate values, we find ...

P = ((-6, 8) +2(6, -7))/3 = (-6+12, 8-14)/3 = (6, -6)/3

P = (2, -2)

4 0

4 years ago

I need help with this question please with an explanation <br> ANSWER ASAP!!!!!!

rjkz [21]

The fish is 2.25 ft above the water surface.

Step-by-step explanation:

Step 1: Given expression for height of the fish above the water surface, y = -16x² + 12x where x is time in seconds. Find height after 0.375 seconds

⇒ y = -16(0.375)² + 12 × 0.375

= -2.25 + 4.5

= 2.25 ft

4 0

3 years ago

In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead. Construct a 95% conden

S_A_V [24]

Answer:

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead.

This means that $n = 42, \pi = \frac{26}{42} = 0.619$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.619 - 1.96\sqrt{\frac{0.619*0.381}{42}} = 0.472$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.619 + 1.96\sqrt{\frac{0.619*0.381}{42}} = 0.766$

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

4 0

3 years ago