Question

At 25 °C, how many dissociated h ions are there in 341 ml of an aqueous solution whose ph is 11. 93?

Answer 1

0.017×$10^{23}$ dissociated H ions are there in 341 ml of an aqueous solution whose ph is 11. 93

If pH = 11.93

pOH = 14.00 - 11.93 = 2.07

[OH- ] = $10^{-2.07}$

[OH-] = 0.00851138 M

In 1 L solution we have 0.00851138 M moles OH- ions

In 0.341 L we have,

0.00851138  * 0.341

=0.0029 moles OH- ions

1 mol OH- ions = 6.022*10²³ ions

0.0029 moles OH- ions = ( 0.0029)  * (6.022*10²³)

= 0.017×$10^{23}$

Therefore,   0.017×$10^{23}$ dissociated H ions are there in 341 ml of an aqueous solution whose ph is 11. 93

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