How many moles of oxygen gas would be needed to completely burn 8 moles of
hydrogen sulfide?
1 answer:
Answer:
12 mol O2
Explanation:
This is assuming you're using a combustion equation of
2 H2S + 3O2 -> 2H2O + 2SO2
Next time include the equation because that is where you will find your mol to mol ratio
8 mol H2S x (3 mol O2 / 2 mol H2S) = 12 mol O2
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Temperature of somewhere.
Answer:
in the 50 place
Explanation:
M(Cs)=133 g/mol
M(O)=16 g/mol
M(CsxOy)=298 g/mol
w(Cs)=0.89
w(O)=0.11
CsxOy
x=M(CsxOy)w(Cs)/M(Cs)
x=298*0.89/133=2
y=M(CsxOy)w(O)/M(O)
y=298*0.11/16=2
Cs₂O₂ cesium peroxide
