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drek231 [11]
3 years ago
13

How many grams of oxygen are in a half a cup of water

Chemistry
1 answer:
USPshnik [31]3 years ago
8 0

Answer:  2.78 moles of molecular oxygen will occupy 62.22 liters.

Explanation:

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The following models represent three different mixtures of the same solid in water,
velikii [3]

Answer:

A

Explanation:

bcuz the water in it is little

3 0
3 years ago
Use the law of conservation of mass to answer the questions. Consider a hypothetical reaction in which A and B are reactants and
shutvik [7]

Answer:

26 grams of D will be produced.

Explanation:

The reaction is given by:

A + B ----->  C + D

Mass of A reacted = 21 g

Mass of B reacted = 22 g

Mass of C formed = 17 g

Mass of D formed = m =?

According to law of conservation of mass, the total mass of the reactants used is equal to the total mass of the product formed.

Then:

mass of A reacted + mass of B reacted = mass of C formed + mass of D formed

21 + 22 = 17 + m

m = 26 g

5 0
3 years ago
MAGNESIUM (Mg)<br> +FLUORINE (F) =
bazaltina [42]

Answer:

MgF2 magnesium fluoride

4 0
3 years ago
Research how different fossil fuels compare in terms of the amount of carbon dioxide released per kWh of energy. How much carbon
pshichka [43]

Answer:

About 19.64 pounds of carbon dioxide are produced from burning a gallon of gasoline. On the other hand, 22.38 pounds of carbon dioxide are produced from burning a gallon of diesel. So, different fossil fuels will give different amounts of carbon dioxide to be released.

Explanation:

5 0
3 years ago
Calculate the freezing point of a solution containing 5. 0 grams of kcl and 550. 0 grams of water. the molal-freezing-point-depr
lutik1710 [3]

The freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is  - 0.45°C

Using the equation,

ΔT_{f} = iK_{f}m

where:

ΔT_{f} = change in freezing point (unknown)

i = Van't Hoff factor

K_{f} = freezing point depression constant

m = molal concentration of the solution

Molality is expressed as the number of moles of the solute per kilogram of the solvent.

Molal concentration is as follows;

MM KCl = 74.55 g/mol

molal concentration = \frac{5.0g*\frac{1mol}{74.55g} }{550.0g*\frac{1kg}{1000g} }

molal concentration = 0.1219m

Now, putting in the values to the equtaion ΔT_{f} = iK_{f}m we get,

ΔT_{f} = 2 × 1.86 × 0.1219

ΔT_{f} = 0.4536°C

So, ΔT_{f} of solution is,

ΔT_{f_{solution} } = 0.00°C - 0.45°C

ΔT_{f_{solution} } =  - 0.45°C

Therefore,freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is  - 0.45°C

Learn more about freezing point here;

brainly.com/question/3121416

#SPJ4

7 0
1 year ago
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