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Crank
3 years ago
13

Which is a characteristic of a Lewis base? it behaves as the electron donor. It behaves as the electron acceptor. It donates a h

ydrogen ion to other compounds. It increases the concentration of hydrogen ions.
Chemistry
2 answers:
Rina8888 [55]3 years ago
5 0

Answer:

It behaves as the electron donor.

Explanation:

Lewis Bases donate an electron pair. Lewis Bases are Nucleophilic meaning that they “attack” a positive charge with their lone pair. They utilize the highest occupied molecular orbital or HOMO (Figure 2). An atom, ion, or molecule with a lone-pair of electrons can thus be a Lewis base.

Dmitry [639]3 years ago
4 0

<em>Answer:</em>

  • It behaves as the electron donar. Its is correct one

<em>Definition of lewis base:</em>

  • Lewis base is a such a substance which donate pair of electron to Lewis acid.

<em>Example:</em>

                                       H3N +  BF3  ⇒   H3N---≥BF3

  • Ammonia is a lewis base while boron trifluride is lewis acid.

<em>Condition</em>

  • There should be lone pair of electron
  • Negative charged substances or anions
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What happens when the pressure of a gas is decreased?
Serggg [28]

Answer:

The combined gas law states that the pressure of a gas is inversely related to the volume and directly related to the temperature. If temperature is held constant, the equation is reduced to Boyle's law. Therefore, if you decrease the pressure of a fixed amount of gas, its volume will increase.

Explanation:

3 0
3 years ago
A first-order reaction (A → B) has a half-life of 25 minutes. If the initial concentration of A is 0.900 M, what is the concentr
Oksanka [162]

Answer:

0.6749 M is the concentration of B after 50 minutes.

Explanation:

A → B

Half life of the reaction = t_{1/2}=25 minutes

Rate constant of the reaction = k

For first order reaction, half life and half life are related by:

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{25 min}=0.02772 min^{-1}

Initial concentration of A = [A]_o=0.900 M

Final concentration of A after 50 minutes = [A]=?

t = 50 minute

[A]=[A]_o\times e^{-kt}

[A]=0.900 M\times e^{-0.02772 min^{-1}\times 50 minutes}

[A] = 0.2251 M

The concentration of A after 50 minutes = 0.2251 M

The concentration of B after 50 minutes = 0.900 M - 0.2251 M = 0.6749 M

0.6749 M is the concentration of B after 50 minutes.

7 0
3 years ago
Tin has ten stable isotopes. The heaviest, 124Sn, makes up 5.80% of naturally occuring tin atoms. How many atoms of 124Sn are pr
matrenka [14]

The average atomic mass of Sn is 118.71 g/mol

the percentage of heaviest Sn is 5.80%

the given mass of Sn is 82g

The total  moles of Sn will be = mass / atomic mass = 82/118.71=0.691

Total atoms of Sn in 82g = 6.023X10^{23}X0.691=4.16X10^{23}

the percentage of heaviest Sn is 5.80%

So the total atoms of Sn^{124} = 5.80% X 4.16X10^{23}

Total atoms of Sn^{124}=2.41X10^{22} atoms

the mass of Sn^{124} will be = \frac{2.41X10^{22}X124}{6.023X10^{23}}=4.96g

5 0
3 years ago
A certain reaction has an activation energy of 25.88 kJ/mol. At what Kelvin temperature will the reaction proceed 6.00 times fas
Juli2301 [7.4K]

Answer:hi

Explanation:

5 0
2 years ago
What is the molar mass of 37.96 g of gas exerting a pressure of 3.29 on the walls of a 4.60 L container at 375 K?
Phantasy [73]

The molar mass of the gas is 77.20 gm/mole.

Explanation:

The data given is:

P = 3.29 atm,   V= 4.60 L   T= 375 K  mass of the gas = 37.96 grams

Using the ideal Gas Law will give the number of moles of the gas. The formula is

PV= nRT    (where R = Universal Gas Constant 0.08206 L.atm/ K mole

Also number of moles is not given so applying the formula

n= mass ÷ molar mass of one mole of the gas.

n = m ÷ x   ( x  molar mass) ( m mass given)

Now putting the values in Ideal Gas Law equation

PV = m ÷ x RT

3.29 × 4.60 = 37.96/x × 0.08206 × 375

15.134 = 1168.1241  ÷ x

15.134x = 1168.1241

x = 1168.1241 ÷ 15.13

x = 77.20 gm/mol

If all the units in the formula are put will get cancel only grams/mole will be there. Molecular weight is given by gm/mole.

8 0
3 years ago
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