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netineya [11]
9 months ago
9

The volume of this regular pentagonal pyramid is 82.5 cubic meters. What is the height of the pyramid?

Mathematics
1 answer:
a_sh-v [17]9 months ago
6 0

the height of the pentagonal pyramid is 5. 70 meters

<h3>Volume of a regular pentagonal pyramid</h3>

The formula for determining the volume of a regular pentagonal pyramid is given as;

V=5/12tan(54°)ha^2

Where

  • a is the base edge
  • h is the height

We have the volume to be;

volume = 82. 5 cubic centers

height = h

a = 5m

Substitute the values

82. 5 = \frac{5}{12} × tan 54 × h ×5^2

82. 5 = 0. 42 × 1. 3764 × 25 × h

Make 'h' subject of formula

h = \frac{82. 5}{14. 45}

h = 5. 70 meters

The height of the pentagonal pyramid is 5. 70 meters

Thus, the height of the pentagonal pyramid is 5. 70 meters

Learn more about a pentagonal pyramid here:

brainly.com/question/16315924

#SPJ1

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Step-by-step explanation:

When we Add or subtract a positive constant, let say c, to input x, it would be a horizontal shift.  

For example:

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y = f(x - c)                      horizontal shift: c units to right

So

Considering the function

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The graph is shown below. The first figure is representing f(x) = x^2.

Now, considering the function

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According to the rule, as we have discussed above, as a positive constant 6 is added to the input, so there is a horizontal shift, 6 units to the right.

The graph of \:f\left(x-6\right)=\left(x-6\right)^2 is shown below in second figure. It is clear that the graph of  \:f\left(x-6\right)=\left(x-6\right)^2  is shifted 6 units to the right as compare to the function f(x) = x^2.

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing f(x) = x^2 and \:f\left(x\right)=\left(x-6\right)^2 is represented as being shifted 6 units to the right as compare to the function f(x) = x^2.

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