If y = cos(kt), then its first two derivatives are
y' = -k sin(kt)
y'' = -k² cos(kt)
Substituting y and y'' into 49y'' = -16y gives
-49k² cos(kt) = -15 cos(kt)
⇒ 49k² = 15
⇒ k² = 15/49
⇒ k = ±√15/7
Note that both values of k give the same solution y = cos(√15/7 t) since cosine is even.
Answer:
I got -64
Step-by-step explanation:
The begging multiplication is 0 and subtract -7 is becomes just -7 then add 3 and it is -4 to the third power is -64
Answer:
The answer is 9
Step-by-step explanation:
All you need to do is divide the two numbers and you will get 9. Trust me I did this one:)
Answer:
Step-by-step explanation:
o=-8
-56=7*(-8)=-56
Answer: 3
Step-by-step explanation: 2+2-1=3
