Use the given graph to determine the period of the function. 1 & 2 plz

Mathematics

1 answer:

White raven [17]3 years ago

6 0

The period of the function is that distance where the function becomes equal again.
We have then:
Part 1:
The period of the function is:
T = 3
Part 2:
The period of the function is:
T = 4
Answer:
The period of functions 1 and 2 respectively are:
T = 3
T = 4

You might be interested in

If a triangle has an area of 108 mm2 and the base of the triangle is 18 mm, what is the height of the triangle?

elena-14-01-66 [18.8K]

Answer:

the height is 12

Step-by-step explanation:

you would take the area (108 mm2), divide that by the base (18 mm) and multiply it by 2

7 0

3 years ago

In a group of 100 people, 70 have a DVD player, 60 have a CD

erma4kov [3.2K]

Answer:

50 people

Step-by-step explanation:

100-70 is 30. 30-20 is 10. 60-10 is 50.

5 0

3 years ago

0 write the quation of the<br> graph

Vika [28.1K]

to get the equation of any straight line, all we need is two points from it, Check the picture below, let's use those two.

$(\stackrel{x_1}{-5}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{(-5)}}}{\underset{run} {\underset{x_2}{0}-\underset{x_1}{(-5)}}}\implies \cfrac{1+5}{0+5}\implies \cfrac{6}{5}$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-5)}=\stackrel{m}{\cfrac{6}{5}}(x-\stackrel{x_1}{(-5)}) \\\\\\ y+5=\cfrac{6}{5}(x+5)\implies y+5=\cfrac{6}{5}x+6\implies y=\cfrac{6}{5}x+1$