Molarity of Vinegar solution is 0.107 M
<u>Explanation:</u>
Let V1 be the volume of NaOH = 13.58 ml
Let V2 be the volume of Vinegar = 14.66 ml
Let M1 be the molarity of NaOH = 0.115 M
Let M2 be the molarity of Vinegar = ?
Using the Law of Volumetric analysis, V1M1= V2M2
Rearranging the equation to get M2 as,
M2 = V1M1/V2 = 13.58 ml * 0.115 M/14.66 ml = 0.107 M
So the Molarity of Vinegar = 0.107 M
Answer:
Liquid from nonvolatile solids can be separated by distillation .
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Answer:
The answer to your question is n = 0.838 moles
Explanation:
Data
Volume = 2.15 l
Pressure = 8.91 atm
Temperature = 5.81°C
moles = ?
Gas constant = 0.082 atm l / mol°K
Process
1.- Convert temperature to °K
Temperature = 5.81 + 273 = 278.81°K
2.- Write the Ideal gas formula
PV = nRT
-Solve for moles (n)
n = PV / RT
3.- Substitution
n = (8.91 x 2.15) / (0.082 x 278.81)
4.- Simplification
n = 19.16 / 22.86
5.- Result
n = 0.838 moles
Answer:
The answer is melting and freezing point.
Explanation: