Answer: 
Explanation:
Given
At temperature 
Volume is 
and the temperature changes to 
At this temperature volume is 
Consider Pressure remains the constant

The volume at this temperature is 
Answer: The partial pressure of the oxygen is 698 torr
Explanation:
According to Dalton's law, the total pressure is the sum of individual pressures.

Given :
=total pressure of gases = 720 torr
= partial pressure of
= ?
= partial pressure of
= 22 torr



Thus the partial pressure of the oxygen is 698 torr
Answer:
The new volume will be 9.24 mL.
Explanation:
Charles's law determines that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases.
So, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

When studying an initial state 1 and a final state 2, it is satisfied:

In this case:
- V1= 8.70 mL
- T1= 318.2 K
- V2= ?
- T2= 337.8 K
Replacing:

Solving:

V2= 9.24 mL
<u><em>The new volume will be 9.24 mL.</em></u>