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elena55 [62]
3 years ago
8

How many moles of C2H2 are needed to react completely with 84.0 mol O2?

Chemistry
2 answers:
Korvikt [17]3 years ago
8 0
<span>How many moles of C2H2 are needed to react completely with 84.0 mol O2?  </span><span> 

33.6 mol C2H<span>2</span></span>
Mama L [17]3 years ago
6 0
The reaction between C2H2 and O2 is as follows:
2C2H2 + 5O2 = 4CO2 + 2H2O

After balancing the equation, the reaction ratio between C2H2 and O2 is 2:5.

The moles of O2 in this reaction is 84.0 mol. According to the above ratio, the moles of C2H2 needed to react completely with the O2 is 84.0mole *2/5 = 33.6 mole.
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How many milliliters o a 0.2% solution o a skin test antigen must be used to prepare 4 mL o a solution containing 0.04 mg/mL o t
Klio2033 [76]

Answer:

0.08 mL

Explanation:

The solution of the skin test has a concentration of 0.2% (w/v), which means that there are 0.2 g of the antigen per 100 mL of the solution. If a new solution will be done using it, then this solution will be diluted, and the mass of the antigen added must be the same in the volume taken and at the diluted solution.

The mass is the concentration (in g/mL) multiplied by the volume of the solution (in mL), so, if m is the mass, C the concentration, V the volume, 1 the initial solution, and 2 the diluted:

m1 = m2

C1*V1 = C2*V2

Where

C1 = 0.2 g/100 mL = 0.002 g/mL

V1 = ?

C2 = 0.04 mg/mL = 0.00004 g/mL

V2 = 4 mL

0.002*V1 = 0.00004*4

V1 = 0.08 mL

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Caffeine, a stimulant in coffee and tea, has a molar mass of 194.19 g/mol and a mass percentage composition of 49.48% C, 5.19% H
lozanna [386]

Answer : The molecular formula of a caffeine is, C_8H_{10}N_4O_2

Solution :

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 49.48 g

Mass of H = 5.19 g

Mass of N = 28.85 g

Mass of O = 16.48 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of N = 14 g/mole

Molar mass of O = 16 g/mole

Step 1 : convert given masses into moles.

Moles of C = \frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{49.48g}{12g/mole}=4.12moles

Moles of H = \frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{5.19g}{1g/mole}=5.19moles

Moles of N = \frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{28.85g}{14g/mole}=2.06moles

Moles of O = \frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{16.48g}{16g/mole}=1.03moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{4.12}{1.03}=4

For H = \frac{5.19}{1.03}=5.03\approx 5

For N = \frac{2.06}{1.03}=2

For O = \frac{1.03}{1.03}=1

The ratio of C : H : N : O = 4 : 5 : 2 : 1

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = C_4H_5N_2O_1=C_4H_5N_2O

The empirical formula weight = 4(12) + 5(1) + 2(14) + 16 = 97 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}

n=\frac{194.19}{97}=2

Molecular formula = (C_4H_5N_2O)_n=(C_4H_5N_2O)_2=C_8H_{10}N_4O_2

Therefore, the molecular of the caffeine is, C_8H_{10}N_4O_2

5 0
3 years ago
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